java - 如何在 "Guess my number "游戏中使用Do While循环？

Question

我正在执行一个名为“猜我的号码”的简单任务，我正在尝试实现我的代码，以便当用户猜到正确的数字时，应用程序会显示“恭喜”并允许用户选择是否再次玩。我认为 do while 循环可以做到这一点，但我仍然不确定如何实现它。有任何想法吗？。提前谢谢您!

这是我的代码，运行得很好。

        Random random = new Random();
        while (true)
        {
            int randomNumber = random.Next(1, 5);
            int counter = 1;
            while (true)
            {
                Console.Write("Guess a number between 1 and 5");
                int input = Convert.ToInt32(Console.ReadLine());

                if (input < randomNumber)
                {
                    Console.WriteLine("Too low, try again.");
                    ++counter;
                    continue;
                }
                else if (input > randomNumber)
                {
                    Console.WriteLine("Too high, try again.");
                    ++counter;
                    continue;
                }
                else
                {
                    Console.WriteLine("Congratulations. You guessed the number!");
                    break;
                }
            }
        }

Answer 1

您可以在最外层循环中添加一个 boolean 标志，以便在用户说“否”时中断:

Random random = new Random();
        while (true)
        {
            int randomNumber = random.Next(1, 5);
            int counter = 1;
            bool retry = true;
            while (true)
            {
                Console.Write("Guess a number between 1 and 5");
                int input = Convert.ToInt32(Console.ReadLine());

                if (input < randomNumber)
                {
                    Console.WriteLine("Too low, try again.");
                    ++counter;
                    continue;
                }
                else if (input > randomNumber)
                {
                    Console.WriteLine("Too high, try again.");
                    ++counter;
                    continue;
                }
                else
                {
                    Console.WriteLine("Congratulations. You guessed the number!");
                    Console.WriteLine("Would you like to retry? y/n");
                    string answer = Console.ReadLine();
                    if (answer != "y")
                    {
                        retry = false;
                    }
                    break;
                }

            }
            if (!retry) break;

        }

对于 do-while 版本:

    bool retry = true;
    Random random = new Random();
    do
    {
        int randomNumber = random.Next(1, 5);
        int counter = 1;

        while (true)
        {
            Console.Write("Guess a number between 1 and 5");
            int input = Convert.ToInt32(Console.ReadLine());

            if (input < randomNumber)
            {
                Console.WriteLine("Too low, try again.");
                ++counter;
                continue;
            }
            else if (input > randomNumber)
            {
                Console.WriteLine("Too high, try again.");
                ++counter;
                continue;
            }
            else
            {
                Console.WriteLine("Congratulations. You guessed the number!");
                Console.WriteLine("Would you like to retry? y/n");
                string answer = Console.ReadLine();
                if (answer != "y")
                {
                    retry = false;
                }
                break;
            }

        }
    } while (retry);