java - 如何解析json中的对象？

Question

我正在尝试解析 json，但它给我错误 java lang.string 无法转换为 jsonArray。这是我的 json 和错误:

Value {"MemberList":[{"MemberId":1,"FirmId":1,"MemberTypeId":1,
"MemberUserName":"test@example.com",      "MemberName":"sth","UpdateDate":"\/Date(1421840040000)\/",
"LastLoginDate":"\/Date(1454995980000)\/",
"FirmTypeId":1,"FirmName":"Firm","FirmOfficialName":"Firm",
"FirmRowGuid":"sth","MemberRowGuid":"sth","AuthToken":"sth",
"IsRegistered":1}],"MemberPageList":null,"FirmModuleList":null,"Status":true,
"StatusCode":"OK"} of type java.lang.String cannot be converted to JSONArray

当我删除 MemberList header 并手动运行时，它工作正常，但我必须使用 header 解析它，我应该如何解析它。 userDetail 是我的 json 字符串:

JSONArray jsonArray = new JSONArray(userDetail);
                    member = new Member();
                    for (int i = 0; i < jsonArray.length(); i++) {

                    JSONObject jsonObject = jsonArray.getJSONObject(i);
                    member.MemberId = jsonObject.optInt("MemberId");
                    member.MemberTypeId = jsonObject.optInt("MemberTypeId");
                    member.FirmTypeId = jsonObject.optInt("FirmTypeId");
                    member.IsRegistered = jsonObject.optInt("IsRegistered");

                    member.MemberUserName = jsonObject.optString("MemberUserName");
                    member.MemberName = jsonObject.optString("MemberName");
                    member.UpdateDate = jsonObject.optString("UpdateDate");
                    member.LastLoginDate = jsonObject.optString("LastLoginDate");
                    member.FirmName = jsonObject.optString("FirmName");
                    member.FirmOfficialName = jsonObject.optString("FirmOfficialName");
                    member.FirmRowGuid = jsonObject.optString("FirmRowGuid");
                    member.MemberRowGuid = jsonObject.optString("MemberRowGuid");
                    member.AuthToken = jsonObject.optString("AuthToken");
                }

Answer 1

它是一个 json 对象而不是数组，因此需要更改，

JSONArray jsonArray = new JSONArray(userDetail);

到

JSONObject jsonObj= new JSONObject(userDetail);
JSONArray jsonArray = jsonObj.getJSONArray("MemberList");

要手动检查 json，请使用此 http://jsoneditoronline.org/

代码:

    JSONObject jsonObj= new JSONObject(userDetail);
    JSONArray jsonArray = jsonObj.getJSONArray("MemberList");

                    for (int i = 0; i < jsonArray.length(); i++) {
                    member = new Member();
                    JSONObject jsonObject = jsonArray.getJSONObject(i);
                    member.MemberId = jsonObject.optInt("MemberId");
                    member.MemberTypeId = jsonObject.optInt("MemberTypeId");
                    member.FirmTypeId = jsonObject.optInt("FirmTypeId");
                    member.IsRegistered = jsonObject.optInt("IsRegistered");

                    member.MemberUserName = jsonObject.optString("MemberUserName");
                    member.MemberName = jsonObject.optString("MemberName");
                    member.UpdateDate = jsonObject.optString("UpdateDate");
                    member.LastLoginDate = jsonObject.optString("LastLoginDate");
                    member.FirmName = jsonObject.optString("FirmName");
                    member.FirmOfficialName = jsonObject.optString("FirmOfficialName");
                    member.FirmRowGuid = jsonObject.optString("FirmRowGuid");
                    member.MemberRowGuid = jsonObject.optString("MemberRowGuid");
                    member.AuthToken = jsonObject.optString("AuthToken");
                }