ios - 弹出 View Controller ，然后同时关闭前一个 View Controller

Question

我的主视图 Controller A 呈现 View Controller B，然后将 View Controller C 推送到其(B 的)导航堆栈上。现在，从C，我希望能够直接到A。如果我从C运行dismissViewController，动画不流畅，如果我将C弹出到B然后关闭B，则有两个单独/不同的动画，其中我不想。

有没有办法让我直接从 C 转到 A 而无需中间过渡？

因此，运行以下(从 C 开始)显示了一个突然的转换

[self dismissViewControllerAnimated:YES completion:nil];

而运行以下(来自C)显示两个单独的转换......

UIViewController *previousViewController = [self.navigationController.viewControllers 
            objectAtIndex:(self.navigationController.viewControllers.count - 2)];
[self.navigationController popViewControllerAnimated:YES];
[previousViewController dismissViewControllerAnimated:YES completion:nil];

Answer 1

使用popToViewController:animated:

[self.navigationController popToViewController: self.navigationController.viewControllers.firstObject animated: YES];

或者，使用 setViewControllers:animated:

NSMutableArray* viewControllers = [self.navigationController.viewControllers mutableCopy];
[viewControllers removeLastObject];
[viewControllers removeLastObject];
[self.navigationController setViewControllers: viewControllers animated: YES];