java - 字符串子串错误

Question

问题:

Input:-gandhi                      output:- Gandhi
Input:-mahatma gandhi              output:- M. Gandhi 
Input:-Mohndas Karamchand ganDhi   output:- M. K. Gandhi

答案:

public class Chef_NITIKA {

    static Scanner scan=new Scanner(System.in);

    public static void main(String[] args) {
        String name=    myString();
        System.out.println("nam is :"+name);
        mySformatter(name);

    }

    private static void mySformatter(String name) {
           int count=0;
          for(char c:name.toCharArray()){
              if(c==' '){
                  count+=1;
              }
          }
          System.out.println(count+" blank spaces");
          if(count==0){
              char ch=name.charAt(0);
              name=Character.toUpperCase(ch)+name.substring(1);
              System.out.println("nam is :"+name);
          }
          else if(count==1){
              char ch=name.charAt(0);
             name= name.replace(' ', '.');
             String subname=name.substring(name.indexOf(".")+1);
             char c=subname.charAt(0);
             subname=Character.toUpperCase(c)+subname.substring(1);
             name=Character.toUpperCase(ch)+"."+subname;
              System.out.println("nam is :"+name);
          }
          else if(count==2){
              char ch=name.charAt(0);
            // name= name.replace(' ', '.');
             String subname=name.substring(name.indexOf(" ")+1);
             System.out.println(subname);
             String subsubname=subname.substring(name.indexOf(" "));
             System.out.println(subsubname);
             char c=subname.charAt(0);
             char c1=subsubname.charAt(0);
             subname=Character.toUpperCase(c)+subname.substring(1);
             name = Character.toUpperCase(ch)+"."+Character.toUpperCase(c)+"."+Character.toUpperCase(c1)+subsubname.substring(1);
              System.out.println("nam is :"+name);
          }
    }

    private static String myString() {
       System.out.println("enter the string");
       String s=scan.nextLine();
       StringBuffer name=new StringBuffer();
     //  name.append(s);
       return s;
    }
}

当我输入“abc cde fgh”时，我没有得到所需的输出，我得到的输出为 A.C..fgh

有什么有效的方法可以解决这个问题吗？

不需要的输出:-

enter the string
iam writing onStack
nam is :iam writing onStack
2 blank spaces
writing onStack
ing onStack
nam is :I.W.Ing onStack

我想要输出为 I.W.OnStack

Answer 1

只需将名称分成几个部分，然后形成您想要的缩写:

public static String getName(String input) {
    String[] names = input.split("\\s+");
    String output = "";

    // replace 1st through second to last names with capitalized 1st letter
    for (int i=names.length; i > 1; --i) {
        output += names[names.length - i].substring(0, 1).toUpperCase() + ". ";
    }

    // append full last name, first letter capitalized, rest lower case
    output += names[names.length - 1].substring(0, 1).toUpperCase()
           + names[names.length - 1].substring(1).toLowerCase();

    return output;
}

public static void main(String[] args) {
    System.out.println(getName("gandhi"));
    System.out.println(getName("mahatma gandhi"));
    System.out.println(getName("Mohndas Karamchand ganDhi"));
}

输出:

Gandhi
M. Gandhi
M. K. Gandhi

此处演示:

Rextester

更新:

这是一个link to a demo我至少部分地纠正了您的原始代码。问题在于以下行:

String subsubname = subname.substring(name.indexOf(" "));

我改成这样:

String subsubname = subname.substring(subname.indexOf(" ") + 1);

您没有正确识别名称第三部分的第一个字符。话虽这么说，您当前的方法很冗长、难以阅读且不灵活。在实践中，您可能希望使用更精简的方法来解决此问题。