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java - JsonArrayRequest 没有给出任何响应

转载 作者:行者123 更新时间:2023-12-01 17:55:20 24 4
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我正在尝试使用 Android Volley 库从远程服务器上的数据库中获取数组。问题是JSONobject没有返回 onResponse 中的任何数据方法。当我尝试显示 JSONobject 中的数据时,应用程序崩溃并且 logcat 显示 NullPointerException。

Java代码如下:

public class AudioFragmentThree extends Fragment {
View view;
TextView text;
String url = "http://www.muftiattaullahmultani.com/android/get_all_bayan.php";
int count = 0;
int i = 0;

@Nullable
@Override
public View onCreateView(LayoutInflater inflater, @Nullable ViewGroup container, Bundle savedInstanceState) {
view = inflater.inflate(R.layout.audio_fragment_three, container, false);
return view;
}

@Override
public void onActivityCreated(@Nullable Bundle savedInstanceState) {
super.onActivityCreated(savedInstanceState);

JsonArrayRequest jsonArrayRequest = new JsonArrayRequest(Request.Method.POST, url, null, new Response.Listener<JSONArray>() {
public void onResponse(JSONArray response) {
while(count<response.length())
{
JSONObject object= null;
try {
object = response.getJSONObject(count);
String s = object.getString("id") +" "+ object.getString("topic");

text.setText(s);

count++;
} catch (JSONException e) {
e.printStackTrace();
}
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
text.setText("ERROR");
}
});

MySingleton.getInstance(getActivity()).addToRequestQueue(jsonArrayRequest);
}
}

LogCat 如下:

FATAL EXCEPTION: main Process: com.example.mashood.muftiattaullahmultanicom, PID: 22596
java.lang.NullPointerException: Attempt to invoke virtual method 'void android.widget.TextView.setText(java.lang.CharSequence)' on a null object reference at
com.example.mashood.muftiattaullahmultanicom.AudioFragmentThree$1.onResponse(AudioFragmentThree.java:81)
at com.example.mashood.muftiattaullahmultanicom.AudioFragmentThree$1.onResponse(AudioFragmentThree.java:69)
at com.android.volley.toolbox.JsonRequest.deliverResponse(JsonRequest.java:65)
at com.android.volley.ExecutorDelivery$ResponseDeliveryRunnable.run(ExecutorDelivery.java:99)
at android.os.Handler.handleCallback(Handler.java:739)
at android.os.Handler.dispatchMessage(Handler.java:95)
at android.os.Looper.loop(Looper.java:135)
at android.app.ActivityThread.main(ActivityThread.java:5910)
at java.lang.reflect.Method.invoke(Native Method)
at java.lang.reflect.Method.invoke(Method.java:372)
at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1405)
at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1200)

下面是我的 PHP 代码:

<?PHP include 'database.php';
$query = 'SELECT * FROM audio_bayan ORDER BY no DESC';
$result = $conn->query($query);
$response = array();
while($row = $result->fetch_assoc()) {
array_push($response,array("id"=>$row['no'],"topic"=>$row['topic']));
}
echo json_encode($response);
?>

最佳答案

您必须像下面这样定义textview:

Textview text;

text = (TextView) view.findViewById(R.id.textid);

关于java - JsonArrayRequest 没有给出任何响应,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45485230/

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