java - 在java中返回多个map

Question

我正在尝试将 void 方法移至它自己的类并返回 map 的键值对(debitCardDetails、creditCardDetails)。返回多个映射并在父类中提取的正确方法是什么，或者我需要合并 Map<String, Map<String, String>> result并返回结果？

public class CardService {

    public void serviceCall(List<CardImplementation> mapDetails) {

        final Map<String, String> debitCardDetailsMap = new HashMap<String, String>();
        final Map<String, String> creditCardDetailsMap = new HashMap<String, String>();

        /*code implementation */
        debitCardDetailsMap.put("type", "VISA");
        debitCardDetailsMap.put("bank", "BofA");
        debitCardDetailsMap.put("rank", "2");

        creditCardDetailsMap.put("type", "VISA");
        creditCardDetailsMap.put("number","23345");
        creditCardDetailsMap.put("bank", "citi");
    }
}

parentClass 看起来像这样

public class ServiceClass {

CardService cardService = new CardService();
  if ( debitCardDetailsMap.size() > 0 ) {
      checkAccount(debitCardDetailsMap);
  }
  if ( creditCardDetailsMap.size()>0 ) {
     checkScore(creditCardDetailsMap);
  }
}

Answer 1

您可以返回carddetailsDTO对象并使用DTO。像下面这样的东西。

mport java.util.Map;

public class CardDetailsDTO {

    private Map<String,String> debitCardDetails;

    private Map<String,String> creditCardDetails;

    public Map<String,String> getCreditCardDetails() {
        return creditCardDetails;
    }

    public void setCreditCardDetails(Map<String,String> creditCardDetails) {
        this.creditCardDetails = creditCardDetails;
    }

    public Map<String,String> getDebitCardDetails() {
        return debitCardDetails;
    }

    public void setDebitCardDetails(Map<String,String> debitCardDetails) {
        this.debitCardDetails = debitCardDetails;
    }


}

现在在主类中你可以返回这个 dto。

如下所示

import java.util.HashMap;
import java.util.List;
import java.util.Map;

public class CardService {

    public CardDetailsDTO serviceCall(List<?> mapDetails) {

        CardDetailsDTO cardDetailsDTO = new CardDetailsDTO();
        final Map<String, String> debitCardDetailsMap = new HashMap<String, String>();
        final Map<String, String> creditCardDetailsMap = new HashMap<String, String>();


        /*code implementation */
        debitCardDetailsMap.put("type", "VISA");
        debitCardDetailsMap.put("bank", "BofA");
        debitCardDetailsMap.put("rank", "2");

        cardDetailsDTO.setDebitCardDetails(debitCardDetailsMap);

        creditCardDetailsMap.put("type", "VISA");
        creditCardDetailsMap.put("number","23345");
        creditCardDetailsMap.put("bank", "citi");

        cardDetailsDTO.setCreditCardDetails(creditCardDetailsMap);

        return cardDetailsDTO;
    }
}