ios - 如何使用标签获取点击哪个按钮

Question

我使用 tag++ 创建了多个按钮。我需要知道使用 sender 方法单击哪个按钮。单击带有标签的按钮时，我需要从数据库中获取值。我应该使用 if 方法作为点击按钮的标签位置吗

button1 = [UIButton buttonWithType:UIButtonTypeRoundedRect];
    [button1 addTarget:self action:@selector(click1:)                                    forControlEvents:UIControlEventTouchDown];
     [button1 setTitle:@"click" forState:UIControlStateNormal];

     button1.frame = CGRectMake(xff, yff, 30.0, 20.0);

    int gTag = 1;                                    

      button1.tag = gTag;
       gTag++;

    [wbCont.scrollView  addSubview:button1];

在这里我需要知道按钮点击:

 -(void)click1:(id)sender{


UIButton *button3=(UIButton *)sender;
switch([button3 tag]){
        //Do the switch case here

        NSArray *coorpaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask, YES);
        NSString *coordocumentsDirectory = [coorpaths objectAtIndex:0];
        NSLog(@"docs dir is %@", coordocumentsDirectory);

        NSString *coorpath = [coordocumentsDirectory stringByAppendingPathComponent:@"ohs.sqlite"];
        NSLog(@"filepath %@",coorpath);

        if (sqlite3_open([coorpath UTF8String], &database) == SQLITE_OK) {


            const char *sql =  [[NSString stringWithFormat:
                                 @"SELECT xcoor,ycoor,artt_id FROM touch where artt_id = %@", artID]cStringUsingEncoding:NSUTF8StringEncoding];


            NSLog(@"getmainsql is %s",sql);

            sqlite3_stmt *statement;

            if (sqlite3_prepare_v2(database, sql, -1, &statement, NULL) == SQLITE_OK) {
                // We "step" through the results - once for each row.
                while (sqlite3_step(statement) == SQLITE_ROW) {



                    xff1=sqlite3_column_double(statement, 0);

                    yff1=sqlite3_column_double(statement, 1);

                    art_Id2 = sqlite3_column_int(statement, 2);

                    NSLog(@"xff1 is %f",xff1);

                    NSLog(@"yff1 is %f",yff1);

                    //  NSLog(@"zc is %@",zc);

                    NSLog(@"art_Id is %ld",(long)art_Id2);


                }

            }

        }


}

Answer 1

发件人返回执行该操作的对象。首先将发件人类型转换为按钮，您可以拥有该对象可实现的所有属性

-(void)click1:(id)sender{
    UIButton *button=(UIButton *)sender;
    switch([button tag]){
    //Do the switch case here
    }
}

所以在你的情况下

 -(void)click1:(id)sender{

        UIButton *button=(UIButton *)sender;
NSInteger tag = [button tag];
if( tag){
 NSArray *coorpaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask, YES);
    NSString *coordocumentsDirectory = [coorpaths objectAtIndex:0];
    NSLog(@"docs dir is %@", coordocumentsDirectory);
    NSString *coorpath = [coordocumentsDirectory stringByAppendingPathComponent:@"ohs.sqlite"];
    NSLog(@"filepath %@",coorpath);
    if (sqlite3_open([coorpath UTF8String], &database) == SQLITE_OK) {
        const char *sql =  [[NSString stringWithFormat:
                             @"SELECT xcoor,ycoor,artt_id FROM touch where artt_id = %@", artID]cStringUsingEncoding:NSUTF8StringEncoding];
        NSLog(@"getmainsql is %s",sql);
        sqlite3_stmt *statement;
        if (sqlite3_prepare_v2(database, sql, -1, &statement, NULL) == SQLITE_OK) {
            // We "step" through the results - once for each row.
            while (sqlite3_step(statement) == SQLITE_ROW) {
                xff1=sqlite3_column_double(statement, 0);
                yff1=sqlite3_column_double(statement, 1);
                art_Id2 = sqlite3_column_int(statement, 2);
                NSLog(@"xff1 is %f",xff1);
                NSLog(@"yff1 is %f",yff1);
                //  NSLog(@"zc is %@",zc);
                NSLog(@"art_Id is %ld",(long)art_Id2);
    }
   }
 }
}

更新

是的，你可以使用它

笔记

使用 UIControlEventTouchUpInside用于实现按钮的点击事件

[button addTarget:self action:@selector(click1:) forControlEvents:UIControlEventTouchUpInside];