java - 如何检查 char 是否为某个字符

Question

已关闭。这个问题是 not reproducible or was caused by typos 。目前不接受答案。

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这个问题是由拼写错误或无法再重现的问题引起的。虽然类似的问题可能是 on-topic在这里，这个问题的解决方式不太可能帮助 future 的读者。

已关闭 5 年前。

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我想请某人输入一封信，当他们输入时，检查该字母是否是我要问他们的某个字母。如果是，我的输出将显示数组列表。我的代码:

import java.util.Scanner;
Scanner input = new Scanner(System.in);
public static void main(String[] args) {        
    String[] rodent;
    String[] dog;
    String[] cat;

    rodent = new String[] {"Rat", "Guinea Pig", "Mouse"};
    dog = new String[] {"Rottweiler", "Basset Hound", "Weiner Dog"};
    cat = new String[] {"Lion", "Tiger", "Mountain Lion"};

    Scanner input = new Scanner(System.in);

    System.out.print("Please Enter [R] for Rodent, [D] for Dogs, and"
            + " [C] for Cats: ");
    char character = input.next().charAt(0);

    if(character == 'R'); {
        System.out.print(rodent[0]+", "+rodent[1]+", "+rodent[2]);
        } // closes 'R' statement
    if(character == 'D') {
        System.out.print(dog[0]+", "+dog[1]+", "+dog[2]);
    } //closes 'D' statement
    if(character == 'C') {
        System.out.print(cat[0]+", "+cat[1]+", "+cat[2]);
    } //closes 'C' statement
}

如果他们输入 R，它就会正确输出。

如果输入 D，则会输出啮齿动物和狗。

如果它们输入 C，则仅输出啮齿动物。

解决这个问题的方法是什么？

Answer 1

这确实是因为不需要的分号，但始终尝试使用 switch-case 结构进行此类检查以获得最佳实践。

Scanner input = new Scanner(System.in);

public static void main(String[] args) {
    String[] rodent;
    String[] dog;
    String[] cat;

    rodent = new String[] {"Rat", "Guinea Pig", "Mouse"};
    dog = new String[] {"Rottweiler", "Basset Hound", "Weiner Dog"};
    cat = new String[] {"Lion", "Tiger", "Mountain Lion"};

    Scanner input = new Scanner(System.in);

    System.out.print("Please Enter [R] for Rodent, [D] for Dogs, and"
            + " [C] for Cats: ");
    char character = input.next().charAt(0);


    switch (character){
        case 'R': System.out.print(rodent[0]+", "+rodent[1]+", "+rodent[2]);break;
        case 'D': System.out.print(dog[0]+", "+dog[1]+", "+dog[2]);break;
        case 'C': System.out.print(cat[0]+", "+cat[1]+", "+cat[2]);break;
    }
}