ios - 将字典数组拆分为子数组

Question

以下是我的JSON响应的一部分，其中“results”是一个字典数组:

{
  "results": [
    {
      "id": 6,
      "genre_name": "Action",
      "cover_image": "http://54.254.204.81/images/Action.png"
    },
    {
      "id": 5,
      "genre_name": "Adventure",
      "cover_image": "http://54.254.204.81/images/Adventure.png"
    },
    {
      "id": 4,
      "genre_name": "Romance",
      "cover_image": "http://54.254.204.81/images/Romance.png"
    },
    {
      "id": 3,
      "genre_name": "Sci-Fci",
      "cover_image": "http://54.254.204.81/images/Sci-Fi.png"
    },
    {
      "id": 1,
      "genre_name": "Guide",
      "cover_image": "http://54.254.204.81/images/Adventure_XHLbNfN.png"
    },
    {
      "id": 2,
      "genre_name": "Horror",
      "cover_image": "http://54.254.204.81/images/Phineas-and-Ferb-Christmas-Wallpaper.jpg"
    },
    {
      "id": 7,
      "genre_name": "Emotional",
      "cover_image": "http://54.254.204.81/images/a0fea991287cf41b6b9c4aa16196517f.jpg"
    },
    {
      "id": 8,
      "genre_name": "abcd",
      "cover_image": "http://54.254.204.81/images/logo_text_S0KyzUW.png"
    }
  ]
}

现在，我有另一个JSON响应，其中“ genres”是一个数组，其中包含对象，这些对象是“ results”键对象为“id”的数组对象的子集。

{
  "genres": [
    3,
    1
  ]
}

现在，我可以将“ results”分成两个数组“ results1”和“ results2”，例如:

{
  "results1": [
    {
      "id": 6,
      "genre_name": "Action",
      "cover_image": "http://54.254.204.81/images/Action.png"
    },
    {
      "id": 5,
      "genre_name": "Adventure",
      "cover_image": "http://54.254.204.81/images/Adventure.png"
    },
    {
      "id": 4,
      "genre_name": "Romance",
      "cover_image": "http://54.254.204.81/images/Romance.png"
    },
    {
      "id": 2,
      "genre_name": "Horror",
      "cover_image": "http://54.254.204.81/images/Phineas-and-Ferb-Christmas-Wallpaper.jpg"
    },
    {
      "id": 7,
      "genre_name": "Emotional",
      "cover_image": "http://54.254.204.81/images/a0fea991287cf41b6b9c4aa16196517f.jpg"
    },
    {
      "id": 8,
      "genre_name": "abcd",
      "cover_image": "http://54.254.204.81/images/logo_text_S0KyzUW.png"
    }
  ]
}

和

{
  "results2": [
    {
      "id": 3,
      "genre_name": "Sci-Fci",
      "cover_image": "http://54.254.204.81/images/Sci-Fi.png"
    },
    {
      "id": 1,
      "genre_name": "Guide",
      "cover_image": "http://54.254.204.81/images/Adventure_XHLbNfN.png"
    }
  ]
}

Answer 1

为此，您需要像这样将NSPredicate与IN和NOT一起使用。

首先从您的两个JSON响应中创建resultArray和genresArray。

NSArray *resultArray = [firstJSONResponse objectForKey:@"results"];
NSArray *genresArray = [secondJSONResponse objectForKey:@"genres"];

现在，使用 resultArray过滤 NSPredicate以获得结果。

对于Result1

NSPredicate *predicate = [NSPredicate predicateWithFormat:@"NOT (id IN %@)",genresArray];
NSArray *firstSplitArray = [resultArray filteredArrayUsingPredicate:predicate];
NSLog(@"%@",firstSplitArray);

对于Result2

predicate = [NSPredicate predicateWithFormat:@"id IN %@",genresArray];
NSArray *secondSplitArray = [resultArray filteredArrayUsingPredicate:predicate];
NSLog(@"%@",secondSplitArray);