java - 如何在 Spring Controller 中读取 JSON 数组值

Question

我想迭代产品并获取名称、代码和价格列表并在我的模型类中设置。任何帮助将非常感激 - 我该如何迭代这个。当我使用 obj.get("Products") 时 - 它只是打印为字符串 - 被困在迭代中。

{
    "id": "skd3303ll333",
    "Products": [{
            "name": "apple",
            "code": "iphone-393",
            "price": "1939"

        },
        {
            "name": "ipad",
            "code": "ipad-3939",
            "price": "900"

        }
    ]
}


@PostMapping(path="/create", consumes=MediaType.APPLICATION_JSON_VALUE)
public ResponseEntity<Object> create(@RequestBody  Map<String, Object> obj ) { 
System.out.println("Products :" + obj.get("Products"));
  }

Answer 1

有两种方法可以做到这一点，

1)通过类型转换(我个人不喜欢这个)

List<Map<Object,Object>> productslist = (List<Map<Object, Object>>) obj.get("products");
    for(Map entry: productslist) {
        for(Object s: entry.keySet()) {
            System.out.println(s.toString());
            System.out.println(entry.get(s).toString());

        }
    }

2) 直接映射到模型类，对于这种方法，您需要在构建路径中使用 Jackson 库

@JsonIgnoreProperties(unknown =true)
public class Customer {

@JsonProperty("id")
private String id;
@JsonProperty("products")
private List<Products> products;

public String getId() {
    return id;
}

public void setId(String id) {
    this.id = id;
}

public List<Products> getProducts() {
    return products;
}

public void setProducts(List<Products> products) {
    this.products = products;
   }

}
 @JsonIgnoreProperties(unknown =true)
 class Products{
@JsonProperty("name")
private String name;
@JsonProperty("code")
private String code;
@JsonProperty("price")
private String price;

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public String getCode() {
    return code;
}

public void setCode(String code) {
    this.code = code;
}

public String getPrice() {
    return price;
}

public void setPrice(String price) {
    this.price = price;
   }

}

Controller

public ResponseEntity<Object> create(@RequestBody  Customer obj ) {