java - 在执行正确的代码后，如何阻止我的代码执行每个 println？

Question

    Scanner scan = new Scanner(System.in);

    System.out.print("Enter 2 numbers: ");
    int num1 = scan.nextInt();
    int num2 = scan.nextInt();
    System.out.println("Numbers Saved! Choose your operator + - * / ");
    String operator = scan.next();
    int result;

    result = (operator.equals("+")) ? (num1 + num2) : (num1);
    System.out.println("The addition result is " +result);
    result = (operator.equals("-")) ? (num1 - num2) : (num1);
    System.out.println("The subtraction result is " +result);
    result = (operator.equals("*")) ? (num1 * num2) : (num1);
    System.out.println("The multiplication result is " +result);
    result = (operator.equals("/")) ? (num1 / num2) : (num1);
    System.out.println("The division result is " +result);



}

}这是我的简单计算器代码，例如，当我选择 + 选项时，它会运行所有 System.out.println 行，我如何防止它执行此操作并仅执行与运算符匹配的 println？

Answer 1

尝试切换:

switch (operator) {
    case "+":
        result = num1 + num2;
        System.out.println("The addition result is " + result);
        break;
    case "-":
        result = num1 - num2;
        System.out.println("The subtraction result is " + result);
        break;
    case "-":
        result = num1 * num2;
        System.out.println("The multiplication result is " + result);
        break;
    case "/":
        result = num1 / num2;
        System.out.println("The integer division result is " + result);
        break;
    default:
        throw IllegalArgumentException("Unsupported operator: " + operator);
}