java - 我有多个 Elasticsearch 的应该案例，但只有第一个有效

Question

我已经分享了出现错误的脚本。它只匹配第一个应该情况，而不匹配其余的情况

 BoolQueryBuilder boolqueryBuilder = new BoolQueryBuilder();
 boolqueryBuilder
            .should(QueryBuilders.matchPhrasePrefixQuery("dishName", (userSearchCriteriaContainer.getSearchString() == null ? "" : userSearchCriteriaContainer.getSearchString())))
            .should(QueryBuilders.termQuery("cuisineTypes", String.valueOf(userSearchCriteriaContainer.getCuisineTypes())) )
            .should(QueryBuilders.termQuery("mealType", String.valueOf(userSearchCriteriaContainer.getDishList())) )
            .should(QueryBuilders.termQuery("preparationTime", String.valueOf(userSearchCriteriaContainer.getPreparationTime())) );

 SearchRequest searchRequest = config.client().prepareSearch("dishes").setQuery(boolqueryBuilder).setExplain(true).setFrom(0).setSize(100).request();

 org.elasticsearch.action.search.SearchResponse response = null;
    try {
        response = config.restClient().search(searchRequest, RequestOptions.DEFAULT);
    } catch (IOException e) {

        e.printStackTrace();
    }

Answer 1

当没有“必须”时，“应该”必须符合条件。

可以将其添加到后面(.minimumShouldMatch(2))

至少两个条件。

boolqueryBuilder
        .should(QueryBuilders.matchPhrasePrefixQuery("dishName", (userSearchCriteriaContainer.getSearchString() == null ? "" : userSearchCriteriaContainer.getSearchString())))
        .should(QueryBuilders.termQuery("cuisineTypes", String.valueOf(userSearchCriteriaContainer.getCuisineTypes())) )
        .should(QueryBuilders.termQuery("mealType", String.valueOf(userSearchCriteriaContainer.getDishList())) )
        .should(QueryBuilders.termQuery("preparationTime", String.valueOf(userSearchCriteriaContainer.getPreparationTime())) )
        .minimumShouldMatch(2);