java - 此代码不接受性别输入，而是直接接受城市的最后输入

Question

这个问题已经有答案了:

Scanner is skipping nextLine() after using next() or nextFoo()? (25 个回答)

已关闭 3 年前。

import java.util.Scanner;

public class Main { 
    public static void main(String [] args) {
        Scanner sc=new Scanner(System.in);

        System.out.println("Enter your name");
        String n=sc.nextLine();

        System.out.println("Enter your age");
        int age=sc.nextInt();

        System.out.println("Enter your gender");
        String g=sc.nextLine();

        System.out.println("Hailing From");
        String c=sc.nextLine();

        System.out.println("Welcome, " +n+ "!");
        System.out.println("Age:" +age);
        System.out.println("Gender:" +g);
        System.out.println("City:" +c);
    }
}

代码不接受性别输入。不知道代码有什么问题？

Answer 1

当你得到nextInt时，你仍然需要走到行尾。请尝试以下操作:

import java.util.Scanner; public class Main {

public static void main(String [] args)      {
Scanner sc=new Scanner(System.in);

System.out.println("Enter your name");
String n=sc.nextLine();

System.out.println("Enter your age");
int age=sc.nextInt();
    sc.nextLine();   //YOU NEED TO ADD THIS LINE!

System.out.println("Enter your gender");
String g=sc.nextLine();

System.out.println("Hailing From");
String c=sc.nextLine();

System.out.println("Welcome, " +n+ "!");
System.out.println("Age:" +age);
System.out.println("Gender:" +g);
System.out.println("City:" +c);
}}