java - 掷骰子游戏问题

Question

该代码的目的是让 2 个玩家掷一对骰子。第一个掷出总点数为 20 的玩家获胜。我无法弄清楚如何正确跟踪掷骰子的总和；它只给出当前回合的总和，然后当每个玩家滚动 10 次时游戏结束。

如何正确计算每个玩家游戏的总和，然后在其中一个玩家的总和等于 20 时停止循环？

int a, b, c, d;
int playerone=0, playertwo=0;

Random gen = new Random();
a=gen.nextInt(6)+1;
b=gen.nextInt(6)+1;
c=gen.nextInt(6)+1;
d=gen.nextInt(6)+1;

while(playerone!=20 || playertwo!=20) {
    playerone=a+b;
    playertwo=c+d;

    System.out.println("Player 1 rolled " + a + " and a " + b );
    System.out.println("Player 1 now has " + playerone);
    System.out.println("Player 2 rolled " + c + " and a " + d );
    System.out.println("Player 2 now has " + playertwo);

    a=gen.nextInt(6)+1;
    b=gen.nextInt(6)+1;
    c=gen.nextInt(6)+1;
    d=gen.nextInt(6)+1;

    playertwo+=a+b;

    playerone+=c+d;
    if(playerone==20) 
        System.out.println("player one wins ");
    else if (playertwo==20)
        System.out.println("player two wins ");             
    }       
}

Answer 1

请看一下并将其与您的代码片段进行比较:

int playerone = 0, playertwo = 0;
while(playerone < 20 && playertwo < 20) {
    a=gen.nextInt(6)+1;
    b=gen.nextInt(6)+1;
    c=gen.nextInt(6)+1;
    d=gen.nextInt(6)+1;

    System.out.println("Player 1 rolled " + a + " and a " + b );
    System.out.println("Player 1 now has " + playerone);
    System.out.println("Player 2 rolled " + c + " and a " + d );
    System.out.println("Player 2 now has " + playertwo);

    playerone+=a+b;
    playertwo+=c+d;
    }

    if(playerone >= playertwo) { // here you have to choose how
        System.out.println("player one wins with " + playerone + " over " + playertwo);
    } else {
    System.out.println("player two wins with " + playertwo + " over " + playerone);
}

在上面的代码中，我纠正了一些事情，where 条件和 a/b 是针对玩家 1 的，c/d 是针对玩家 2 的。在 where 循环结束后，您必须根据结果值或通过你的逻辑是如何确定获胜者，因为双方都掷骰子。