java - java AES解密函数有什么问题？

Question

我修改了可用的代码 http://java.sun.com/developer/technicalArticles/Security/AES/AES_v1.html

并在程序中制定了加密和解密方法。但我收到 BadpaddingException..该函数也返回 null..为什么会这样？出什么问题了？请帮助我..

这些是我正在使用的变量:

kgen = KeyGenerator.getInstance("AES");
            kgen.init(128);
            raw = new byte[]{(byte)0x00,(byte)0x11,(byte)0x22,(byte)0x33,(byte)0x44,(byte)0x55,(byte)0x66,(byte)0x77,(byte)0x88,(byte)0x99,(byte)0xaa,(byte)0xbb,(byte)0xcc,(byte)0xdd,(byte)0xee,(byte)0xff};
            skeySpec = new SecretKeySpec(raw, "AES");
            cipher = Cipher.getInstance("AES");

            plainText=null;
            cipherText=null;

以下是解密函数..

public String decrypt(String cipherText)
    {
        try
        {
            cipher.init(Cipher.DECRYPT_MODE, skeySpec);
            byte[] original = cipher.doFinal(cipherText.getBytes());
            plainText = new String(original);
        }


        catch(BadPaddingException e)
        {

        }

        return plainText;
    }

Answer 1

来自Java-Security archives

One common mistakes that people made is to put the encrypted bytes inside astring and upon decryption they use String.getBytes() to retrieve it.Since String does its own character encoding, the byte[] that you used toconstruct the String object and the byte[] that you get from its getBytes()are not necessarily equal.