ios - 对数组进行排序，其中包含日期，月份

Question

我想根据日期和月份值对数组进行排序。我正在使用此代码

 NSSortDescriptor *descriptor=[[NSSortDescriptor alloc]initWithKey:@"self" ascending:YES];
    NSArray *descriptors=[NSArray arrayWithObject:descriptor];
    revereseorder=[dateAarray sortedArrayUsingDescriptors:descriptors];
    NSLog(@"date order %@",revereseorder);

我得到如下响应:

 date order (
    "01-11-2014",
    "01-12-2014",
    "02-11-2014",
    "02-12-2014",
    "03-11-2014",
    "03-12-2014",
    "04-11-2014",
    "04-12-2014",
    "05-11-2014",
    "05-12-2014",
    "06-11-2014",
    "06-12-2014",
    "07-11-2014",
    "07-12-2014",
    "08-11-2014",
    "08-12-2014",
    "09-11-2014",
    "09-12-2014",
    "10-11-2014",
    "10-12-2014",
    "11-11-2014",
    "11-12-2014",
    "12-11-2014",
    "12-12-2014",
    "13-11-2014",
    "13-12-2014",
    "14-11-2014",
    "15-11-2014",
    "16-11-2014",
    "17-11-2014",
    "18-11-2014",
    "19-11-2014",
    "20-11-2014"

)

但是我需要根据当月的降序显示响应的当前日期。请问我如何解决？谢谢@

Answer 1

如果要对字符串进行正确排序，则需要将其转换为实际的NSDate对象。

您可以使用比较器功能像这样对它们进行排序...

NSArray *dateStringArray = //your array...

NSDateFormatter *dateFormatter = [NSDateFormatter new];
dateFormatter.dateFormat = @"dd-MM-yyyy";

NSArray *sortedArray = [dateStringArray sortedArrayUsingComparator:^(NSString *string1, NSString *string2) {
    NSDate *date1 = [dateFormatter dateFromString:string1];
    NSDate *date2 = [dateFormatter dateFromString:string2];

    return [date1 compare:date2];
}];

如果要降序，只需将比较器的最后一行更改为...

return [date2 compare:date1];