json - 在 Excel VBA 代码中处理 XMLHttp 响应中的 JSON 对象

Question

我需要处理一个 JSON 对象，它是 Excel VBA 中 XMLHTTPRequest 的响应。我写了下面的代码，但它不起作用:

  Dim sc As Object
  Set sc = CreateObject("ScriptControl")
  sc.Language = "JScript"

  Dim strURL As String: strURL = "blah blah"

  Dim strRequest
  Dim XMLhttp: Set XMLhttp = CreateObject("msxml2.xmlhttp")
  Dim response As String

  XMLhttp.Open "POST", strURL, False
  XMLhttp.setrequestheader "Content-Type", "application/x-www-form-urlencoded"
  XMLhttp.send strRequest
  response = XMLhttp.responseText
  sc.Eval ("JSON.parse('" + response + "')")

我在 Set sc = CreateObject("ScriptControl") 行中收到错误运行时错误“429”ActiveX 组件无法创建对象

解析 JSON 对象后，如何访问 JSON 对象的值？

附注我的 JSON 对象示例:{"Success":true,"Message":"Blah blah"}

Answer 1

代码从 nseindia 站点获取数据，该数据以 JSON 字符串形式存在于 responseDiv 元素中。

所需引用文献

我用过的3类模块

• cJSONScript
• cStringBuilder
• JSON

(我从 here 中选择了这些类模块)

您可以从此link下载该文件

标准模块

Const URl As String = "http://www.nseindia.com/live_market/dynaContent/live_watch/get_quote/GetQuote.jsp?symbol=ICICIBANK"
Sub xmlHttp()

    Dim xmlHttp As Object
    Set xmlHttp = CreateObject("MSXML2.ServerXMLHTTP.6.0")
    xmlHttp.Open "GET", URl & "&rnd=" & WorksheetFunction.RandBetween(1, 99), False
    xmlHttp.setRequestHeader "Content-Type", "text/xml"
    xmlHttp.send

    Dim html As MSHTML.HTMLDocument
    Set html = New MSHTML.HTMLDocument
    html.body.innerHTML = xmlHttp.ResponseText

    Dim divData As Object
    Set divData = html.getElementById("responseDiv")
    '?divData.innerHTML
    ' Here you will get a string which is a JSON data

    Dim strDiv As String, startVal As Long, endVal As Long
    strDiv = divData.innerHTML
    startVal = InStr(1, strDiv, "data", vbTextCompare)
    endVal = InStr(startVal, strDiv, "]", vbTextCompare)
    strDiv = "{" & Mid(strDiv, startVal - 1, (endVal - startVal) + 2) & "}"


    Dim JSON As New JSON

    Dim p As Object
    Set p = JSON.parse(strDiv)

    i = 1
    For Each item In p("data")(1)
       Cells(i, 1) = item
       Cells(i, 2) = p("data")(1)(item)
        i = i + 1
    Next

 End Sub