java - 国际象棋游戏如果棋子阻挡了主教/皇后，则删除对角线移动(java)

Question

我正在用 Java 制作国际象棋游戏。

我做了一个 JFrame，它可以让我创建棋子，这就是为什么我对任何棋子都有所有可能的走法(并且我将制作比正常国际象棋中更多的棋子)。

但是我有一个小问题，我已经尝试删除主教的移动两天了，但这并不像看起来那么容易。

我有一个包含片段位置的数组，如下所示:

_______ PIECES[x][y] //1 is black 0 is no piece 2 is white
1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
2 2 2 2 2 2 2 2 
2 2 2 2 2 2 2 2 
_______ legalmoves[y][x] //Containing legal moves 1 is move/attack 0 cannot move there
// ( (x,y) (its y x in this tab)
// is reverse because it needs to be somewhere else in the code this is not a big deal)
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
1 0 0 0 0 0 0 0 
0 1 0 0 0 0 0 0 
0 0 1 0 0 0 0 0 
0 0 0 1 0 0 0 1 
0 0 0 0 1 0 1 0 
0 0 0 0 0 0 0 0 
My piece X,Y : 5 7

当需要知道棋子的合法走法并且检测到该棋子有对角走法时，调用该函数对于这一部分，这里的合法 Action 应该是这样的

0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0

因为还有其他棋子(白色)阻挡移动

提前谢谢您，如果您愿意(如果它可以帮助您帮助我)，我可以为您提供车的运动功能(当检测到直线运动时，它也适用于女王以及我创建的任何作品)有这样的 Action )。车代码:

boolean t = false;
   if (hasRectMoves) {
    System.out.println(x + " XY " + y);
    System.out.println("HAS RECT MOVES !");
    System.out.println("_______ PIECES");
    for (int i = 0; i < 8; i++) {
     for (int j = 0; j < 8; j++) {
      System.out.print(pieces[i][j] + " ");
     }
     System.out.println("");
    }
    System.out.println("_______ RES");
    for (int i = 0; i < 8; i++) {
     //System.out.println("i = "+ i);
     for (int j = 0; j < 8; j++) {
      System.out.print(res[j][i] + " ");
     }
     System.out.println("");
    }
    System.out.println("My piece : " + (x + 1) + " " + (y + 1));
    boolean test = true;

    for (int i = y; i >= 0; i--) {
     //res[x+1][i]=0;
     if (test) {
      if (pieces[i][x + 1] != 0) {
       if (this.isBlack) {
        if (pieces[i][x + 1] == 1)
         res[x + 1][i] = 4;//4 to seen in the array where it makes move illegal
       }
       if (!this.isBlack) {
        if (pieces[i][x + 1] == 2)
         res[x + 1][i] = 4;
       }
       // System.out.println(i + " "+ pieces[i][y+1] + " "  + (x+1) + "=x y="+ (y+1)); 
       test = false;
      }
     } else {
      res[x + 1][i] = 4;
     }

    }
    test = true;
    for (int i = x; i >= 0; i--) {
     //res[x+1][i]=0;
     if (test) {
      if (pieces[y + 1][i] != 0) {
       if (this.isBlack) {
        if (pieces[y + 1][i] == 1)
         res[i][y + 1] = 4;
       }
       if (!this.isBlack) {
        if (pieces[y + 1][i] == 2)
         res[i][y + 1] = 4;
       }
       // System.out.println(i + " "+ pieces[i][y+1] + " "  + (x+1) + "=x y="+ (y+1)); 
       test = false;
      }
     } else {
      res[i][y + 1] = 4;
     }

    }
    test = true;
    for (int i = x + 2; i < 8; i++) {
     //res[x+1][i]=0;
     if (test) {
      if (pieces[y + 1][i] != 0) {
       if (this.isBlack) {
        if (pieces[y + 1][i] == 1)
         res[i][y + 1] = 4;
       }
       if (!this.isBlack) {
        if (pieces[y + 1][i] == 2)
         res[i][y + 1] = 4;
       }
       // System.out.println(i + " "+ pieces[i][y+1] + " "  + (x+1) + "=x y="+ (y+1)); 
       test = false;
      }
     } else {
      res[i][y + 1] = 4;
     }

    }
    test = true;
    for (int i = y + 2; i < 8; i++) {
     //res[x+1][i]=0;
     if (test) {
      if (pieces[i][x + 1] != 0) {
       if (this.isBlack) {
        if (pieces[i][x + 1] == 1)
         res[x + 1][i] = 4;
       }
       if (!this.isBlack) {
        if (pieces[i][x + 1] == 2)
         res[x + 1][i] = 4;
       }
       // System.out.println(i + " "+ pieces[i][y+1] + " "  + (x+1) + "=x y="+ (y+1)); 
       test = false;
      }
     } else {
      res[x + 1][i] = 4;
     }
    }

Answer 1

不错的项目。

我在 main 中写了一个小例子，所以你可以尝试一下。当然还有改进的空间。

我的输出:

3 XY 4
HAS RECT MOVES !
_______ PIECES
1 1 1 1 1 1 1 1 
1 1 1 1 1 1 1 1 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
2 2 2 2 2 2 2 2 
2 2 2 2 2 2 2 2 
_______ RES
0 0 0 0 0 0 0 5 
6 0 0 0 0 0 6 0 
0 7 0 0 0 7 0 0 
0 0 8 0 8 0 0 0 
0 0 0 9 0 0 0 0 
0 0 8 0 8 0 0 0 
0 7 0 0 0 7 0 0 
6 0 0 0 0 0 6 0 
My piece : 3 4
_______ legalmoves
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 
0 7 0 0 0 7 0 0 
0 0 8 0 8 0 0 0 
0 0 0 9 0 0 0 0 
0 0 8 0 8 0 0 0 
0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 

主教的位置标记为9。我为每个字段添加了一个从 8 开始倒数的评级，规定了该字段距主教的距离。 (我希望这是英文？)

然后你必须将矩形分成 4 个子矩形。对于每个替补，你必须单独计算合法的移动。

请尝试一下。如果您有疑问，请告诉我。

public static void main(String[] args) throws Exception{

        int pieces[][] = new int[8][8];
        int res[][] = new int[8][8];

        int x = 3;
        int y = 4;

        System.out.println(x + " XY " + y);
        System.out.println("HAS RECT MOVES !");
        System.out.println("_______ PIECES");
        for (int i = 0; i < 8; i++) {
            for (int j = 0; j < 8; j++) {
                if(i<2){ pieces[i][j] = 1; }
                if(i>5){ pieces[i][j] = 2; }

                System.out.print(pieces[i][j] + " ");
            }
            System.out.println("");
        }
        System.out.println("_______ RES");
        for (int i = 0; i < 8; i++) {
            for (int j = 0; j < 8; j++) {
                res[i][j] = checkField(i, j, x, y);
                System.out.print(res[i][j] + " ");
            }
            System.out.println("");
        }
        System.out.println("My piece : " + (x) + " " + (y));
        System.out.println("_______ legalmoves");
        // 1. section:
        System.out.println("1. section:");
        calcSection(pieces, res, 0, 0, x, y);
        // 2. section:
        System.out.println("2. section:");
        calcSection(pieces, res, 0, y, x, 7);
        // 3. section:
        System.out.println("3. section:");
        calcSection(pieces, res, x, 0, 7, y);
        // 4. section:
        System.out.println("4. section:");
        calcSection(pieces, res, x, y, 7, 7);

        for (int i = 0; i < 8; i++) {
            for (int j = 0; j < 8; j++) {
                System.out.print(res[i][j] + " ");
            }
            System.out.println("");
        }

    }
    public static int[][] calcSection(int[][] pieces, int[][] res, int recStartX, int recStartY, int recEndX, int recEndY){
        System.out.println(recStartX+ ":"+ recStartY + ":"+ recEndX +":" +recEndY);
        System.out.println("res[i][j] = " + res[5][7]);
        for (int k = 8; k > 0; k--) {
            for (int i = recStartX; i <= recEndX; i++) {
                for (int j = recStartY; j <= recEndY; j++) {
                    if(res[j][i] == k){
                        if(pieces[j][i] > 0){
                            for (int l = recStartX; l <= recEndX; l++) {
                                for (int m = recStartY; m <= recEndY; m++) {
                                    if(res[m][l] <= k){
                                        res[m][l] = 0;
                                    }
                                }
                            }       
                            return res;
                        }
                    }
                }
            }
        }
        return res;        
    }

    public static int checkField(int fieldX, int fieldY, int x, int y){
        //x = 3;
        //y = 2;
        if((fieldY == x )&(fieldX == y )){
            return 9;
        }
        else{
            for (int i = 0; i < 8; i++) {
                if((fieldY == x+i )&(fieldX == y+i )){
                    return 9-i;
                } 
                else if((fieldY == x+i )&(fieldX == y-i )){
                    return 9-i;
                } 
                else if((fieldY == x-i )&(fieldX == y+i )){
                    return 9-i;
                }
                else if((fieldY == x-i )&(fieldX == y-i )){
                    return 9-i;
                }
            }
        }
        return 0;
    }
}