java - 获得线程的控制权然后杀死它

Question

我有一个关于 Java 线程的问题。在我的代码中，

...
client.doSth();
// now need to get hold of the thread that is initiated by 'client'
(get a reference to the 'client' thread)
// now kills it
(kills the 'client' thread)
...

所以我想知道的是:在第一个括号中，如何以编程方式获取对“客户端”线程(而不是程序运行的主线程)的引用，在第二个括号中，我如何正确地杀死它，即不使用折旧的 stop() 方法。

非常感谢。

Answer 1

要显示线程树，请这样做:

你可以这样做:

// Find the root thread group
ThreadGroup root = Thread.currentThread().getThreadGroup().getParent();
while (root.getParent() != null) {
    root = root.getParent();
}

// Visit each thread group
visit(root, 0);

// This method recursively visits all thread groups under `group'.
public static void visit(ThreadGroup group, int level) {
    // Get threads in `group'
    int numThreads = group.activeCount();
    Thread[] threads = new Thread[numThreads*2];
    numThreads = group.enumerate(threads, false);

    System.out.println("    ");

    // Enumerate each thread in `group'
    for (int i=0; i<numThreads; i++) {
        // Get thread
        Thread thread = threads[i];
        System.out.println(thread.toString());
    }

    // Get thread subgroups of `group'
    int numGroups = group.activeGroupCount();
    ThreadGroup[] groups = new ThreadGroup[numGroups*2];
    numGroups = group.enumerate(groups, false);

    // Recursively visit each subgroup
    for (int i=0; i<numGroups; i++) {
        visit(groups[i], level+1);
        }

}

您可以选择调用显示指定线程 ID 的 stackTrace 的方法:

 System.out.println(thread.dumpStack());

现在你有了要杀死的 id :

int idToKill = 2;
int active = Thread.activeCount();
System.out.println("currently active threads: " + active);
Thread all[] = new Thread[active];
Thread.enumerate(all);
for (int i = 0; i < active; i++) {
  System.out.println(i + ": " + all[i]);
  if(idToKill == i)
    ((Thread) all[i]).interrupt();
}