Spring Security/j_spring_security_check 未找到 404

Question

这是我的 WebAppInitializer:

@Configuration
public class WebAppInitializer extends AbstractAnnotationConfigDispatcherServletInitializer {

    @Override
    protected Class<?>[] getRootConfigClasses() {
        return new Class<?>[] { AppConfig.class, WebSecurityConfig.class };
    }

    @Override
    protected Class<?>[] getServletConfigClasses() {
        return new Class<?>[] { WebConfig.class };
    }

    @Override
    protected String[] getServletMappings() {
        return new String[] { "/" };
    }
}

这是我的安全配置:

@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private UserDetailsService userDetailsService;

    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userDetailsService);
    }

    @Override
    public void configure(WebSecurity web) throws Exception {
        web.ignoring().antMatchers("/resources/**");
    }

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        // @formatter:off
        http.authorizeRequests()
                .antMatchers("/signup", "/about").permitAll()
                .antMatchers("/admin/**").hasRole("ADMIN")
                .anyRequest().authenticated()
                .and().formLogin().loginPage("/login").defaultSuccessUrl("/home").failureUrl("/error").permitAll()
                .and().httpBasic();
        // @formatter:on
    }

}

这是我的login.html(来自thymeleaf的示例html):

<form th:action="@{/j_spring_security_check}" method="post">
  <label for="j_username">Username</label>:
  <input type="text" id="j_username" name="j_username" /> <br />

  <label for="j_password">Password</label>:
  <input type="password" id="j_password" name="j_password" /> <br />

  <input type="submit" value="Log in" />
</form>

当我点击登录时，出现此错误:

HTTP ERROR 404

Problem accessing /j_spring_security_check. Reason:

    Not Found

如何消除这个错误？我用谷歌搜索了很多，但还没有成功。 (是的，我不使用任何 xml。)

Answer 1

如果您使用的是 spring 4.X，则可能是版本问题

a.) login url = /login b.) logout url = /logout

如 spring 3.X 所示

a.) login url = /j_spring_security_check b.) logout url = /j_spring_security_logout