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java - 删除方法不起作用(使用 Hashmap)

转载 作者:行者123 更新时间:2023-12-01 17:30:25 25 4
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我正在开一家员工商店。 employeeStore中的删除功能不起作用。它没有删除员工,而是没有任何作用,任何人都看不出有什么问题。

这是我的代码:主要

case 3:
System.out.println("Delete by Name.");
Employee employeeDelete = MenuMethods.userInputByName();
Store.searchByName(employeeDelete.getEmployeeName());
System.out.println("Your choice is: "+ employeeDelete);
Store.remove(employeeDelete);
break;

删除方法

// ---------------------------------------------------------------------------------------
// Name: Remove.
// ---------------------------------------------------------------------------------------
public Employee remove(Employee key) {
// Remove the Employee by name.
if (map.containsKey(key))
return map.remove(key); // if its there remove and return
else
return null; // if its not there return 0x00000000 address
}

菜单方法

//---------------------------------------------------------------------------------------
// Name: Imports.
// Description: To allow the use of different Java classes.
//---------------------------------------------------------------------------------------
import java.util.Scanner;
//---------------------------------------------------------------------------------------
public class MenuMethods
{
private static Scanner keyboard = new Scanner(System.in);
//---------------------------------------------------------------------------------------
// Methods for the Company Application menu.
//---------------------------------------------------------------------------------------

//---------------------------------------------------------------------------------------
// Name: getMenuChoice.
// Description: Method for validating the choice.
//---------------------------------------------------------------------------------------
public static int getMenuChoice(String menuString, int limit,String prompt, String errorMessage)
{
System.out.println(menuString);
int choice = inputAndValidateInt(1, limit, prompt, errorMessage);
return choice;
}

//---------------------------------------------------------------------------------------
// Name: inputAndValidateInt.
// Description: This method is used in the getMenuChoice method.
//---------------------------------------------------------------------------------------
public static int inputAndValidateInt(int min, int max, String prompt,String errorMessage)
{
int number;
boolean valid;
do
{
System.out.print(prompt);
number = keyboard.nextInt();
valid = number <= max && number >= min;
if (!valid)
{
System.out.println(errorMessage);
}
} while (!valid);
return number;
}

//---------------------------------------------------------------------------------------
// Name: userInput
// Description: This method is used in the MainApp to give the user capability to enter
// the details when adding details of an employee into the store.
//---------------------------------------------------------------------------------------
public static Employee userInput()
{
String temp = keyboard.nextLine();
Employee e = null;
System.out.println("Please enter the Employee Name:");
String employeeName = keyboard.nextLine();
System.out.println("Please enter the Employee ID:");
int employeeId = keyboard.nextInt();
temp = keyboard.nextLine();
System.out.println("Please enter the Employee E-mail address:");
String employeeEmail = keyboard.nextLine();
return e = new Employee(employeeName, employeeId, employeeEmail);

}

//---------------------------------------------------------------------------------------
// Name: userInputByName.
// Description: This method is used in the MainApp to give the user capability to search by name.
//---------------------------------------------------------------------------------------
public static Employee userInputByName()
{
// String temp is for some reason needed. If it is not included
// The code will not execute properly.
String temp = keyboard.nextLine();
Employee e = null;
System.out.println("Please enter the Employee Name:");
String employeeName = keyboard.nextLine();

return e = new Employee(employeeName);

}

//---------------------------------------------------------------------------------------
// Name: userInputByEmail
// Description: This method is used in the MainApp to give the user capability to search by email.
//---------------------------------------------------------------------------------------
public static String userInputByEmail()
{
// String temp is for some reason needed. If it is not included
// The code will not execute properly.
String temp = keyboard.nextLine();
Employee e = null;
System.out.println("Please enter the Employee Email:");
String employeeEmail = keyboard.nextLine();
// This can use the employeeName's constructor because java accepts the
// parameters instead
// of the name's.
return employeeEmail;

}
//---------------------------------------------------------------------------------------

}

员工

//---------------------------------------------------------------------------------------
// Employee class.
//---------------------------------------------------------------------------------------
public class Employee
{
//---------------------------------------------------------------------------------------
// Variables to be used in the employee store.
//---------------------------------------------------------------------------------------
private String employeeName;
private int employeeId;
private String employeeEmail;
//---------------------------------------------------------------------------------------
// Name: Constructors.
// Description:
//---------------------------------------------------------------------------------------
public Employee(String employeeName, int employeeId, String employeeEmail)
{
this.employeeName = employeeName;
this.employeeId = employeeId;
this.employeeEmail = employeeEmail;
}
//---------------------------------------------------------------------------------------
// Overloading the constructor for the use with userInputByName method.
//---------------------------------------------------------------------------------------
public Employee(String employeeName)
{
this.employeeName = employeeName;
}
//---------------------------------------------------------------------------------------
// Name: Getters.
//---------------------------------------------------------------------------------------
public String getEmployeeEmail()
{
return employeeEmail;
}

public String getEmployeeName()
{
return employeeName;
}
public int getEmployeeId()
{
return employeeId;
}
//---------------------------------------------------------------------------------------
// Name: Setters.
//---------------------------------------------------------------------------------------
public void setEmployeeEmail(String employeeEmail)
{
this.employeeEmail = employeeEmail;
}
public void setEmployeeName(String employeeName)
{
this.employeeName = employeeName;
}
public void setEmployeeId(int employeeId)
{
this.employeeId = employeeId;
}

//---------------------------------------------------------------------------------------
// Name: toString.
//---------------------------------------------------------------------------------------
public String toString()
{
return "\t\t\tEmployee\n" +
"********************************************************************\n"+
"Employee Name: "+ employeeName +"\n"+
"Employee Id: " + employeeId +"\n"+
"Employee Email: " + employeeEmail;
}
//---------------------------------------------------------------------------------------
}

最佳答案

这个方法

public static Employee userInputByName

正在创建一个员工。 (它还毫无意义地将它分配给局部变量......这里的代码风格真的很奇怪 - 就像对 nextLine() 的无关调用一样。)

除非您在 Employee 中覆盖了 equalshashCode,否则它不会认为new Employee 对象等于 HashMap 中的现有对象。不幸的是,您没有向我们展示 Employee 类,但想必它的目的是在员工具有相同名称的情况下将其比较为相等(并给出相同的哈希代码)。

关于java - 删除方法不起作用(使用 Hashmap),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11615658/

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