java - 警告 "unchecked call"和 "unchecked conversion"

Question

当我编译代码时，我收到 4 个警告 - 但如何让它们消失？(我的意思不是@SuppressWarnings)

PS:显然这一定是以前被问过的 - 但要么我找不到它，要么我无法应用它。

<小时/>

输出

warning: [unchecked] unchecked call to BaseWorker(C) as a member of the raw type BaseWorker
[warn] return new BaseWorker(this);

warning: [unchecked] unchecked conversion
[warn] found   : com.crashnote.BaseWorker
[warn] required: com.crashnote.BaseWorker<C>
[warn] return new BaseWorker(this);

warning: [unchecked] unchecked call to SubWorker(C) as a member of the raw type SubWorker
[warn] return new SubWorker(this);

warning: [unchecked] unchecked conversion
[warn] found   : com.crashnote.SubWorker
[warn] required: com.crashnote.SubWorker<C>
[warn] return new SubWorker(this);

<小时/>

源代码

BaseConfig:实例化BaseWorker

public class BaseConfig<C extends BaseConfig> {

    public BaseConfig(final Object c) {
    }

    public BaseWorker<C> getWorker() {
        return new BaseWorker(this);
    }
}

基础工作人员

public class BaseWorker<C extends BaseConfig> {

    public BaseWorker(final C config) {
    }
}

SubConfig:实例化SubWorker

class SubConfig<C extends SubConfig> extends BaseConfig<C> {

    public SubConfig(final Object c) {
        super(c);
    }

    @Override
    public SubWorker<C> getWorker() {
        return new SubWorker(this);
    }
}

SubWorker:继承自SubWorker

public class SubWorker<C extends BaseConfig> extends BaseWorker<C> {

      public SubWorker(final C config) {
          super(config);
      }  
}

<小时/>

编辑

我尝试了提供的解决方案，但由于某种原因它现在失败了。

A)

return new BaseWorker<BaseConfig>(this);

结果

incompatible types
[error] found   : BaseWorker<BaseConfig>
[error] required: BaseWorker<C>
[error] return new BaseWorker<BaseConfig>(this);

B)

return new BaseWorker<C>(this);

结果

cannot find symbol
[error] symbol  : constructor BaseWorker(BaseConfig<C>)
[error] location: class BaseWorker<C>
[error] return new BaseWorker<C>(this);

嗯，也许我做错了什么。顺便说一下，这是 Java 6，以防万一。

Answer 1

而不是返回普通的

return new BaseWorker(this);

使其通用，因为您的 BaseWorker 类被定义为通用类。

return new BaseWorker<C>(this);

同样的规则也适用于 SubWorker。

return new SubWorker<C>(this);

更新:

根据异常消息，您的构造函数还缺少泛型。