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java - JSON 在响应中返回空值

转载 作者:行者123 更新时间:2023-12-01 17:26:52 26 4
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我的响应给了我null值,但是当我在fiddler中运行相同的值时,我得到了大量数据。我编写的代码非常少,并使用在线工具来生成代码。我想知道我哪里搞砸了。

    Publications response = null ;
// First open URL connection (using JDK; similar with other libs)
try {
URL url = new URL(
"http://myserver:myport/Mobile/GetPublications");
HttpURLConnection connection = (HttpURLConnection)url.openConnection() ;
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setRequestMethod("POST") ;
connection.setRequestProperty("Content-Type", "application/json") ;
// and other configuration if you want, timeouts etc
// then send JSON request
Publications request = new Publications(); // POJO with getters or public fields
ObjectMapper mapper = new ObjectMapper();
mapper.writeValue(connection.getOutputStream(), request);
// and read response
response = mapper.readValue(
connection.getInputStream(), Publications.class);
} catch (JsonGenerationException e) {
e.printStackTrace();
fail() ;
} catch (JsonMappingException e) {
e.printStackTrace();
fail() ;
} catch (IOException e) {
e.printStackTrace();
fail() ;
}
assertNotNull(response) ;
assertTrue(response.getPublicationInfo() != null) ;
// assertTrue(response.getPublicationInfo().size() > 0);
// assertNotNull( ((PublicationInfo)response.getPublicationInfo().get(0)).getPublicationTitle() != null) ;

出版物 POJO 是

import com.fasterxml.jackson.*

@JsonSerialize(include = JsonSerialize.Inclusion.NON_NULL)
@Generated("com.googlecode.jsonschema2pojo")
@JsonPropertyOrder({ "ErrorInfo", "PublicationInfo" })
public class Publications {

@JsonProperty("ErrorInfo")
private Object ErrorInfo;

@JsonProperty("PublicationInfo")
private List<PublicationInfo> PublicationInfo = new ArrayList<PublicationInfo>();
private Map<String, Object> additionalProperties = new HashMap<String, Object>();

@JsonProperty("ErrorInfo")
public Object getErrorInfo() {
return ErrorInfo;
}

@JsonProperty("ErrorInfo")
public void setErrorInfo(Object ErrorInfo) {
this.ErrorInfo = ErrorInfo;
}

@JsonProperty("PublicationInfo")
public List<PublicationInfo> getPublicationInfo() {
return PublicationInfo;
}

@JsonProperty("PublicationInfo")
public void setPublicationInfo(
List<PublicationInfo> PublicationInfo) {
this.PublicationInfo = PublicationInfo;
}

@JsonAnyGetter
public Map<String, Object> getAdditionalProperties() {
return this.additionalProperties;
}

@JsonAnySetter
public void setAdditionalProperties(String name, Object value) {
this.additionalProperties.put(name, value);
}
}

我在 assertTrue(response.getPublicationInfo().size() > 0); 处遇到测试用例失败。但 fiddler 返回以下内容

{
"SpecialPublications": {
"ErrorInfo": null,
"SpecialPublicationInfo": [
{
"Date": "2/3/2010",
"URL": "SOME URL HERE",
"Description": "So much to do so less time."
},
{
"Date": "2/4/2010",
"URL": "SOME MORE URL HERE",
"Description": "I need more time"
}
]
}
}

最佳答案

您应该在所有位置将 @JsonProperty("PublicationInfo") 更改为 @JsonProperty("SpotlightPublicationInfo")。您的属性名称错误。

@JsonProperty 的语义是:json 中出现的属性名称。

编辑 还要从 json 中删除虚假属性名称。替换:

response = mapper.readValue(connection.getInputStream(), Publications.class);

与:

JsonNode responseJson = mapper.readTree(connection.getInputStream());
response = mapper.readValue(responseJson.traverse().getValueAsString("SpecialPublications"), Publications.class);

这将去除您尝试解析的对象的虚假 {"SpecialPublications": ... } 包装器。

关于java - JSON 在响应中返回空值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14195945/

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