java - 如何将函数和方法合并到 Java 中的 if-else 条件中？

Question

我能够运行一个程序来计算形状的周长并使用 if-else 条件来确定它是什么形状。但是，我正在努力将 if-else 条件与函数和方法配对。

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);
    int sideA;
    int sideB;
    int sideC;
    int sideD;
    int perimeter = 0;

    System.out.println("Enter side 1: ");
    sideA = scan.nextInt();

    System.out.println("Enter side 2: ");
    sideB = scan.nextInt();

    System.out.println("Enter side 3: ");
    sideC = scan.nextInt();

    System.out.println("Enter side 4: ");
    sideD = scan.nextInt();

    System.out.println("Forms a square with a perimeter of " + perimeter);
    System.out.println("Forms a rectangle with a perimeter of " + perimeter);
    System.out.println("Does not form a rectangle or square.");
}

private static int add(int sideA, int sideB, int sideC, int sideD) {     
    int perimeter = sideA + sideB + sideC + sideD;
    return perimeter;
}

private static void isSquare(int sideA, int sideB, int sideC, int sideD, int perimeter) {
if (sideA == sideB && sideB == sideC && sideC == sideD && sideD == sideA) {
        System.out.println("Forms a square with a perimeter of " + perimeter);
    }

    else if (sideA == sideC && sideB == sideD) {
        System.out.println("Forms a rectangle with a perimeter of " + perimeter);
      }

    else if (sideA == sideB && sideC == sideD) {
        System.out.println("Forms a rectangle with a perimeter of " + perimeter);
      }

    else if (sideA == sideD && sideB == sideC) {
        System.out.println("Forms a rectangle with a perimeter of " + perimeter);
      }

    else {
        System.out.println("Does not form a rectangle or square.");
    }
}

我正在处理的程序在解析时遇到到达文件末尾的问题。如何改进文件的末尾以便我的程序完成解析？

Answer 1

我的意思是你应该考虑调用你的方法 add 和 isSquare也许将你的变量移到 main 之外，这样它们就有更多的作用域

    add(sideA,sideB,sideC,sideD);
    isSquare(sideA,sideB,sideC,sideD,perimeter);