ios - 从ActionSheet移除红色破坏性按钮

Question

我正在尝试弹出一个没有破坏性按钮的操作表。如果我只是尝试从下面的代码中删除破坏性按钮，则会收到错误消息:UIActionSheet没有可见的界面。有人知道为什么会这样吗？如何删除红色的破坏性按钮？谢谢!

UIActionSheet *popupQuery = [[UIActionSheet alloc] initWithTitle:@"Title" 
delegate:self cancelButtonTitle:@"Cancel Button" destructiveButtonTitle:@"Destructive 
Button" otherButtonTitles:@"Other Button 1", @"Other Button 2", nil];

Answer 1

只需将nil作为destructiveButtonTitle 传递即可。

只需尝试以下代码:

UIActionSheet *popupQuery = [[UIActionSheet alloc] initWithTitle:@"Title" delegate:self cancelButtonTitle:@"Cancel Button" destructiveButtonTitle:nil otherButtonTitles:@"Other Button 1", @"Other Button 2", nil];