java - 无法让这款井字游戏公平进行

Question

这是一个跟我合作的井字游戏。我最初在学期初创建了这个游戏，但是老师希望我们现在添加一个 AI(人工智能)，它可以模仿其他玩家。我采取的最好方法是创建一个具有随机数生成器的方法。这对我有用，但是当我运行井字棋游戏时，第二个玩家人工智能会覆盖第一个玩家的 Action 。因此，为了防止这种情况发生，我放入了一个条件语句，可以检查 Jbuttun 是否被禁用。但是它不允许我编译。然后它给出的错误是不兼容的类型:(必需 boolean 值:找到 Void)。

import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import javax.swing.border.*;
import java.util.*;

public class TicTacToe extends JFrame
{
private final int HEIGHT = 450;
private final int WIDTH = 500;
private static JButton [] button = new JButton[9];
private static Action [] playerTurn = new Action[9];
private Font arial = new Font("Arial", Font.BOLD, 20);
private static int lockButtons = 0;
private boolean game = false;
private static Random  rNum = new  Random(); 



public TicTacToe ()
{
    setTitle( "TTT");
    setSize( HEIGHT, WIDTH);
    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);


    setLayout(new GridLayout(4,3));

    int num = 0;
    for(int i = 0; i < 9; i++ )
    {

        button[i] = new JButton( "B" + (i + 1));
        playerTurn[i] = new Action();
        add(button[i]);
        button[i].setBorder(BorderFactory.createLineBorder(Color.black,10));
        button[i].setFont(arial);
        button[i].addActionListener(playerTurn[i]);
    }


    setVisible(true);
}

private class Action implements ActionListener
{
    public void actionPerformed(ActionEvent playerMove)
    {
        //Get button pressed using GetSource Command
        JButton whatPlayer=(JButton)(playerMove.getSource()); 

                for ( int x =0; x <= button.length; x++)
                {
                    whatPlayer.setText("o");
                    whatPlayer.setEnabled(false);
                    validate();
                    JOptionPane.showMessageDialog(null," Computer's Turn ");
                    player2();
                    break;
                }
    }

    public void player2()
    {
        for ( int i = 0; i <= button.length ; i++)
        {   
                    int num = rNum.nextInt(8);
                    button[num].setText( "x");
                    button[num].setEnabled(false);
                    validate();

                // This is the block that is causing the compiler error 
                /*if( button[i].setEnabled(false))
                {
                    JOptionPane.showMessageDialog(null," Button is disables ");
                    break;
                }*/
                    break;
        }       
    }

    public void validate()
    {
        if(button[0].getText().equals(button[1].getText()) && button[1].getText().equals(button[2].getText()))
        {
            JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[0].getText());
            gameOver();
            return;
        }
        else if(button[3].getText().equals(button[4].getText()) && button[4].getText().equals(button[5].getText()))
        {
            JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[3].getText());
            gameOver();
            return;
        }
        else if(button[6].getText().equals(button[7].getText()) && button[7].getText().equals(button[8].getText()))
        {
            JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[6].getText());
            gameOver();
            return;
        }
        else if(button[0].getText().equals(button[3].getText()) && button[3].getText().equals(button[6].getText()))
        {
            JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[0].getText());
            gameOver();
            return;
        }
        else if(button[1].getText().equals(button[4].getText()) && button[4].getText().equals(button[7].getText()))
        {
            JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[1].getText());
            gameOver();
            return;
        }
        else if(button[2].getText().equals(button[5].getText()) && button[5].getText().equals(button[8].getText()))
        {
            JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[2].getText());
            gameOver();
            return;
        }
        else if(button[0].getText().equals(button[4].getText()) && button[4].getText().equals(button[8].getText()))
        {
            JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[0].getText());
            gameOver();
            return;
        }
        else if(button[2].getText().equals(button[4].getText()) && button[4].getText().equals(button[6].getText()))
        {
            JOptionPane.showMessageDialog(null,"Thank you the winner is" + button[2].getText());
            gameOver();
            return;
        }

        int i;

        for(i=0;i<button.length;i++)
        {
            if(button[i].isEnabled())
            {
                break;
            }
        }
        if(i == button.length)
        {
            JOptionPane.showMessageDialog(null,"This was a Draw");
        }
    }
    public void gameOver()
    {
        for( int x = 0; x < button.length; x++)
        {
            button[x].setEnabled(false);
        }
    }
}
public static void main(String[] arg)
{
    new TicTacToe();
}   
}

Answer 1

if( button[i].setEnabled(false))
{
    JOptionPane.showMessageDialog(null," Button is disables ");
    break;
}

您确实试图在条件语句中检查 void 类型，这是不可能的。由于 setEnabled 返回 void(什么也没有)。您应该做的是检查“Enabled”的 getter 方法，因此:

if (!button[i].isEnabled()) {
    JOptionPane.showMessageDialog(null," Button is disables ");
    break;
}

注意“!”在声明之前，这使其变得消极