sql-server - 为什么 SQL 中是 199.96 - 0 = 200？

Question

我有一些客户收到奇怪的账单。我能够隔离核心问题:

SELECT 199.96 - (0.0 * FLOOR(CAST(1.0 AS DECIMAL(19, 4)) * CAST(199.96 AS DECIMAL(19, 4)))) -- 200 what the?
SELECT 199.96 - (0.0 * FLOOR(1.0 * CAST(199.96 AS DECIMAL(19, 4)))) -- 199.96
SELECT 199.96 - (0.0 * FLOOR(CAST(1.0 AS DECIMAL(19, 4)) * 199.96)) -- 199.96

SELECT 199.96 - (CAST(0.0 AS DECIMAL(19, 4)) * FLOOR(CAST(1.0 AS DECIMAL(19, 4)) * CAST(199.96 AS DECIMAL(19, 4)))) -- 199.96
SELECT 199.96 - (CAST(0.0 AS DECIMAL(19, 4)) * FLOOR(1.0 * CAST(199.96 AS DECIMAL(19, 4))))                         -- 199.96
SELECT 199.96 - (CAST(0.0 AS DECIMAL(19, 4)) * FLOOR(CAST(1.0 AS DECIMAL(19, 4)) * 199.96))                         -- 199.96

-- It gets weirder...
SELECT (0 * FLOOR(CAST(1.0 AS DECIMAL(19, 4)) * CAST(199.96 AS DECIMAL(19, 4)))) -- 0
SELECT (0 * FLOOR(1.0 * CAST(199.96 AS DECIMAL(19, 4))))                         -- 0
SELECT (0 * FLOOR(CAST(1.0 AS DECIMAL(19, 4)) * 199.96))                         -- 0

-- so... ... 199.06 - 0 equals 200... ... right???
SELECT 199.96 - 0 -- 199.96 ...NO....

有谁知道这里到底发生了什么吗？我的意思是，它肯定与十进制数据类型有关，但我无法真正理解它......

<小时/>

对于数字文字是什么数据类型有很多困惑，所以我决定显示真实的行:

PS.SharePrice - (CAST((@InstallmentCount - 1) AS DECIMAL(19, 4)) * CAST(FLOOR(@InstallmentPercent * PS.SharePrice) AS DECIMAL(19, 4))))

PS.SharePrice DECIMAL(19, 4)

@InstallmentCount INT

@InstallmentPercent DECIMAL(19, 4)

我确保每个操作的结果都具有不同于 DECIMAL(19, 4) 类型的操作数，然后再将其应用到外部上下文。

尽管如此，结果仍然是 200.00。

<小时/>

我现在创建了一个简化的示例，你们可以在计算机上执行。

DECLARE @InstallmentIndex INT = 1
DECLARE @InstallmentCount INT = 1
DECLARE @InstallmentPercent DECIMAL(19, 4) = 1.0
DECLARE @PS TABLE (SharePrice DECIMAL(19, 4))
INSERT INTO @PS (SharePrice) VALUES (599.96)

-- 2000
SELECT
  IIF(@InstallmentIndex < @InstallmentCount,
  FLOOR(@InstallmentPercent * PS.SharePrice),
  1999.96)
FROM @PS PS

-- 2000
SELECT
  IIF(@InstallmentIndex < @InstallmentCount,
  FLOOR(@InstallmentPercent * CAST(599.96 AS DECIMAL(19, 4))),
  1999.96)
FROM @PS PS

-- 1996.96
SELECT
  IIF(@InstallmentIndex < @InstallmentCount,
  FLOOR(@InstallmentPercent * 599.96),
  1999.96)
FROM @PS PS

-- Funny enough - with this sample explicitly converting EVERYTHING to DECIMAL(19, 4) - it still doesn't work...
-- 2000
SELECT
  IIF(@InstallmentIndex < @InstallmentCount,
  FLOOR(@InstallmentPercent * CAST(199.96 AS DECIMAL(19, 4))),
  CAST(1999.96 AS DECIMAL(19, 4)))
FROM @PS PS

<小时/>

现在我得到了一些东西......

-- 2000
SELECT
  IIF(1 = 2,
  FLOOR(CAST(1.0 AS decimal(19, 4)) * CAST(199.96 AS DECIMAL(19, 4))),
  CAST(1999.96 AS DECIMAL(19, 4)))

-- 1999.9600
SELECT
  IIF(1 = 2,
  CAST(FLOOR(CAST(1.0 AS decimal(19, 4)) * CAST(199.96 AS DECIMAL(19, 4))) AS INT),
  CAST(1999.96 AS DECIMAL(19, 4)))

到底是什么 - 地板无论如何都应该返回一个整数。这里发生了什么？ :-D

<小时/>

我想我现在已经成功地将其归结为本质:-D

-- 1.96
SELECT IIF(1 = 2,
  CAST(1.0 AS DECIMAL (36, 0)),
  CAST(1.96 AS DECIMAL(19, 4))
)

-- 2.0
SELECT IIF(1 = 2,
  CAST(1.0 AS DECIMAL (37, 0)),
  CAST(1.96 AS DECIMAL(19, 4))
)

-- 2
SELECT IIF(1 = 2,
  CAST(1.0 AS DECIMAL (38, 0)),
  CAST(1.96 AS DECIMAL(19, 4))
)

Answer 1

我需要先将其展开一点，以便我可以看到发生了什么:

SELECT 199.96 - 
    (
        0.0 * 
        FLOOR(
            CAST(1.0 AS DECIMAL(19, 4)) * 
            CAST(199.96 AS DECIMAL(19, 4))
        )
    ) 

现在让我们看看 SQL Server 在减法运算的每一端使用什么类型:

SELECT  SQL_VARIANT_PROPERTY (199.96     ,'BaseType'),
    SQL_VARIANT_PROPERTY (199.96     ,'Precision'),
    SQL_VARIANT_PROPERTY (199.96     ,'Scale')

SELECT  SQL_VARIANT_PROPERTY (0.0 * FLOOR(CAST(1.0 AS DECIMAL(19, 4)) * CAST(199.96 AS DECIMAL(19, 4)))  ,'BaseType'),
    SQL_VARIANT_PROPERTY (0.0 * FLOOR(CAST(1.0 AS DECIMAL(19, 4)) * CAST(199.96 AS DECIMAL(19, 4)))  ,'Precision'),
    SQL_VARIANT_PROPERTY (0.0 * FLOOR(CAST(1.0 AS DECIMAL(19, 4)) * CAST(199.96 AS DECIMAL(19, 4)))  ,'Scale')

结果:

numeric 5   2numeric 38  1

So 199.96 is numeric(5,2) and the longer Floor(Cast(etc)) is numeric(38,1).

The rules for the resulting precision and scale of a subtraction operation (ie: e1 - e2) look like this:

Precision: max(s1, s2) + max(p1-s1, p2-s2) + 1
Scale: max(s1, s2)

That evaluates like this:

Precision: max(1,2) + max(38-1, 5-2) + 1 => 2 + 37 + 1 => 40
Scale: max(1,2) => 2

You can also use the rules link to figure out where the numeric(38,1) came from in the first place (hint: you multiplied two precision 19 values).

But:

• The result precision and scale have an absolute maximum of 38. When a result precision is greater than 38, it is reduced to 38, and the corresponding scale is reduced to try to prevent the integral part of a result from being truncated. In some cases such as multiplication or division, scale factor will not be reduced in order to keep decimal precision, although the overflow error can be raised.

Oops. The precision is 40. We have to reduce it, and since reducing precision should always cut off the least significant digits that means reducing scale, too. The final resulting type for the expression will be numeric(38,0), which for 199.96 rounds to 200.

You can probably fix this by moving and consolidating the CAST() operations from inside the large expression to one CAST() around the entire expression result. So this:

SELECT 199.96 - 
    (
        0.0 * 
        FLOOR(
            CAST(1.0 AS DECIMAL(19, 4)) * 
            CAST(199.96 AS DECIMAL(19, 4))
        )
    ) 

变成:

SELECT CAST( 199.96 - ( 0.0 * FLOOR(1.0 * 199.96) ) AS decimial(19,4))

我什至可能还会去掉外壳。

我们在这里了解到，我们应该选择与我们现在实际拥有的精度和规模相匹配的类型，而不是预期的结果。仅仅采用大精度数字是没有意义的，因为 SQL Server 会在算术运算期间改变这些类型以避免溢出。

<小时/>

更多信息:

• Precision, Scale, and Length using Sql_Variant_Property()
• Operator Precedence
• Data type precedence