java - 我无法让我的石头、剪刀、布程序读取正确的结果

Question

每当我运行它时，似乎继续玩的循环都有效，但是每当 computerChoose 执行 randomGenerator 时，游戏结果都不会正确输出。请帮忙。我是java新手，我们只打算使用3种方法——指令、playGame和computerChoose。我们还假设使用用户控制的循环来继续工作。我似乎无法做到这一点，我仍然需要添加一个循环来计算游戏已玩的次数、获胜的次数以及计算机获胜的次数。

import java.util.*;

public class PRS {

    public static Scanner kbd = new Scanner(System.in);

    public static void instructions() {

        System.out.println("\nThis is the popular game of paper, rock, scissors.  Enter your"
                + "\nchoice by typing the word \"paper\", the word \"rock\" or the word"
                + "\n\"scissors\".  The computer will also make a choice from the three"
                + "\noptions.  After you have entered your choice, the winner of the"
                + "\ngame will be determined according to the following rules:"
                + "\n\nPaper wraps rock (paper wins)"
                + "\nRock breaks scissors (rock wins)"
                + "\nScissors cuts paper (scissors wins)"
                + "\n\nIf both you and the computer enter the same choice, then the game "
                + "\nis tied.\n");

    }

    public static int playGame(){

        int outcome = 0;
        System.out.print("Enter your choice: ");
        kbd = new Scanner(System.in);
        String player = kbd.nextLine().toLowerCase();
        String computerChoice = computerChoose();
        System.out.println("\nYou entered: " + player);
        System.out.println("Computer Chose: " + computerChoose());

        if(player.equals(computerChoose())){

            outcome = 3;


        } 

        else if (player.equals("paper") && computerChoice.equals("rock")){

            outcome = 1;

        }
        else if (computerChoice.equals("paper") && player.equals("rock")){

            outcome = 2;
        }
        else if (player.equals("rock") && computerChoice.equals("scissors")){


            outcome = 1;


        }
        else if (computerChoice.equals("rock") && player.equals("scissors")){
            outcome = 2;

        }

        else if (player.equals("scissors") && computerChoice.equals("paper") ){

            outcome = 1;
        }

        else if (computerChoice.equals("scissors") && player.equals("paper")){

            outcome = 2;
        }

        else if (player.equals("rock") && computerChoice.equals("paper") ){

            outcome = 2;
        }

        else if (computerChoice.equals("rock") && player.equals("paper")){

            outcome = 1;
        }
        return outcome;

    }


    public static String computerChoose(){

        /*return "scissors";*/
        Random generator = new Random();
        String [] answer = new String [3];
        answer [0]= "paper";
        answer [1] = "rock";
        answer [2] = "scissors";
        return answer[generator.nextInt(3)];

    }

    public static void main(String[] args) {


        kbd = new Scanner(System.in);

        System.out.println("THE GAME OF PAPER, ROCK, SCISSORS:");

        System.out.print("\nDo you need instructions (Y or N)? ");

        String userPlay = kbd.nextLine();

        if (userPlay.equalsIgnoreCase("y")){
            instructions();
        }




        String answer;
        do{

            int result = playGame();

            System.out.println(result);
            switch (result){
            case 1: 
                System.out.println("YOU WIN!");
                break;
            case 2: 
                System.out.println("Comp WINs!");
                break;
            case 3: 
                System.out.println("IT'S A TIE!");
                break;
            default:
            }

            System.out.print("\nPlay again ( Y or N)? ");
            answer = kbd.nextLine();

        }while(answer.equalsIgnoreCase("y"));


    }


}   

Answer 1

您需要做的第一件事就是仅调用一次 computerChoose() 。每次调用此方法时，它都会生成一个新的随机数，从而产生不同的答案。您应该只在 playGame() 中调用它一次并将其分配给局部变量。

例如

String computerChoice = computerChoose();

然后用此变量名称替换对 computerChoose() 的所有其他调用。这样，您将显示一个值并仅比较逻辑中的一个值。

至于跟踪其他信息，例如游戏数量和获胜/失败的数量，请考虑声明更多的类变量(或主方法中的局部变量)，然后您可以对其进行赋值、递增和读取。您可以在 main 方法的 do-while 循环中完成所有这些操作。不需要任何额外的循环。