Java运行程序

Question

这是一个非常简单的程序。我创建了一个新类，我将定义一个新方法来在新类中调用下一步。

public class MyClass {

    public static void main(String[] args) {
        int number = 1;
        public void showSomething(){
            System.out.println("This is my method "+number+" created by me.");
        }

    }
}

但是，当我运行这个程序时，我遇到了一个错误:

Exception in thread "main" java.lang.Error: Unresolved compilation problems: 
    Syntax error on token(s), misplaced construct(s)
    Syntax error on token "void", @ expected

Answer 1

错误是因为您在另一个方法中声明了一个方法，这里是 main()。

更改此:

public static void main(String[] args) {
    int number = 1;
    public void showSomething(){
        System.out.println("This is my method "+number+" created by me.");
    }

}

到

public static void main(String[] args) {
    int number = 1;
    showSomething(); // call the method showSomething()
}
public static void showSomething(){
    System.out.println("This is my method "+number+" created by me.");
}

此外，showSomething() 也应声明为 static，因为 main() 是 static。只能从另一个静态方法调用静态方法。