java - 编写一个程序来读取未指定数量的整数

Question

“计算正数和负数并计算数字的平均值)编写一个程序，读取未指定数量的整数，确定读取了多少个正值和负值，并计算输入值的总和和平均值(不是计数零)。您的程序以输入 0 结束。将平均值显示为 float 。”

我不知道我做错了什么

import java.util.Scanner;

public class NewClass {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

        int positive = 0, negative = 0, total = 0, count = 0;

        double average;

        System.out.println("Enter the number: ");
        int number;

        while ((number = input.nextInt()) != 0) {
            total += number;
            count++;
            if (number > 0) {
                positive++;
            } else if (number < 0) {
                negative++;
            }
        }
        average = total / count;
        System.out.println("The number of positives is " + positive);
        System.out.println("The number of negatives is " + negative);
        System.out.println("The total is " + total);
        System.out.printf("The average is %d ", average);
    }
}

Answer 1

第一:应该是average = (double)total / count;因为 int/int 比你得到一个整数。

第二个:System.out.println("The average is " + average);或System.out.printf("The average is %f ", average);