java - 如何搜索file.txt中包含字符串的行

Question

当我想在文件中搜索字符串行时遇到问题，这是我的代码

public static void main( String[] args ) throws SQLException
    {
        try{
        //System.out.println( "Hello World!" );
             RepositoryFactory.emf=Persistence.createEntityManagerFactory("onezero");
        String Symbol = "EURUSD";
        TradingHistory tradingHistorys = RepositoryFactory.getTradingHistoryRepo().findPriceEmpty(Symbol);
        String symbols = tradingHistorys.getSymbol();
        String created = tradingHistorys.getCreated_at();
        String[] createds = created.split(" ");
        String tanggal = createds[0];
        String times = createds[1];
        String timeSearch = tanggal.concat("T").concat(times);
        String pathfile = "/home/ec2-user/saveFile/";
        String filesearch = pathfile.concat(tanggal).concat("-").concat(symbols).concat(".txt");
        SearchFile(timeSearch,filesearch);

        System.out.print(symbols+"|"+created+"|"+filesearch+timeSearch);
    }catch (Exception e){
        System.out.print(e);
    }
    }

这是我在文件中搜索字符串的方法

private static void SearchFile(String timeSearch, String filesearch) {
        String line = null;
        ArrayList<String> fileContents = new ArrayList<String>();
         try {
                FileReader fReader = new FileReader(filesearch);
                BufferedReader fileBuff = new BufferedReader(fReader);
                while ((line = fileBuff.readLine()) != null) {
                    fileContents.add(line);
                }
                fileBuff.close();
            } catch (Exception e) {
                System.out.println(e.getMessage());
            }
         System.out.println(fileContents.contains(timeSearch));
    }

当我使用

时

Scanner fileScanner = new Scanner(new File(filesearch));
          int lineID = 0;
          java.util.List lineNumbers = new ArrayList();
          Pattern pattern =  Pattern.compile(timeSearch);
          Matcher matcher = null;
          while(fileScanner.hasNextLine()){
                String line = fileScanner.nextLine();
                lineID++;
                matcher = pattern.matcher(line);
                if(matcher.find()){
                    lineNumbers.add(lineID);

                }


            }
            System.out.println(lineNumbers);
        }

我得到了[183394、183395、183396、183397、183398、183399、183400、183401、183402、183403、183404、183405、183406]

当我运行我的代码时，我收到错误，错误。但是当我搜索手册时，值是

文件名称为 2020-05-05-EURUSD.txt 欧元/美元|1.09031|2020-05-05T04:30:17.008 欧元/美元|1.0903|2020-05-05T04:30:17.046 欧元/美元|1.09029|2020-05-05T04:30:17.211 欧元/美元|1.0903|2020-05-05T04:30:17.340 欧元/美元|1.09027|2020-05-05T04:30:17.348 欧元/美元|1.0903|2020-05-05T04:30:17.509 欧元/美元|1.09027|2020-05-05T04:30:17.518 欧元/美元|1.0903|2020-05-05T04:30:17.547 欧元/美元|1.09027|2020-05-05T04:30:17.558 欧元/美元|1.0903|2020-05-05T04:30:17.712 欧元/美元|1.09027|2020-05-05T04:30:17.718 欧元/美元|1.0903|2020-05-05T04:30:17.841 欧元/美元|1.09027|2020-05-05T04:30:17.848

如何修复 file.txt 中的搜索字符串？

这是我得到的日志

false
EURUSD|2020-05-05 04:30:17|2020-05-05 04:30:17/home/ec2-user/saveFile/2020-05-05-EURUSD.txt2020-05-05T04:30:17

Answer 1

fileContents.contains(timeSearch)检查 fileContents 的任何元素(文件的每一行)是否等于 timeSearch

您应该对 fileContents 的每个元素(文件的每一行)使用 String contains() 方法

public static void main(String[] args) {
    String filePath2 = Paths.get("").toAbsolutePath().toString();
    String path = filePath2.concat("\\files\\2020-05-05-EURUSD.txt");
    searchFile("2020-05-05T04:30:17", path);
}

private static void searchFile(String timeSearch, String filesearch) {
    String line = null;
    ArrayList<String> fileContents = new ArrayList<String>();
     try {
            FileReader fReader = new FileReader(filesearch);
            BufferedReader fileBuff = new BufferedReader(fReader);
            while ((line = fileBuff.readLine()) != null) {
                fileContents.add(line);
            }
            fileBuff.close();
        } catch (Exception e) {
            System.out.println(e.getMessage());
        }
     System.out.println(fileContents.contains(timeSearch));

     boolean result =false;
     for (String elementOfArrayList : fileContents) {
        if(elementOfArrayList.contains(timeSearch)) {
            result=true;
            break;
        }
    }
     System.out.println(result);
}