java - try catch 阶乘递归函数的异常

Question

当我合并 try -catch 方法时，我希望我的阶乘输出一条打印出“无效错误。没有负数”的语句，但每次它都不打印我的错误语句。这是我的代码:

import java.util.Scanner;
import javax.swing.JOptionPane;

public class App {

public static void main(String[] args) {
    int value;
   //E.g. 4!=4*3*2*1
    Scanner keyboard=new Scanner(System.in);
    System.out.println("Enter a value for factorial");
    value=keyboard.nextInt();
    try{
    System.out.println(calculate(value));}catch(NumberFormatException e){

        System.out.println("invalid error. No negative numbers");

    }

}

private static int calculate(int value){


    if(value==1 || value==0){
        return 1;
    }
    return  calculate(value-1)*value;

}

}

我做错了什么

Answer 1

你还没有抛出异常

private static int calculate(int value) throws NumberFormatException {

    if (value < 0) throw new NumberFormatException("invalid error. No negative numbers");
    if(value==1 || value==0){
        return 1;
    }
    return  calculate(value-1)*value;

}