java - 如果 HTTPStatus Code 不等于 200，则响应实体为 null

Question

我刚刚开始使用Spring框架并进行一些测试。我正在尝试联系 ResponseEntity。但如果 HTTP 状态代码不等于 200，则 ResponseEntity 对象始终为 null。因此我无法访问状态代码或 header 。

如果HTTP状态代码不等于200，有什么办法可以到达ResponseEntity吗？

public static String checkPatientExistence(String pNo, String eNo) throws RestClientException, NullPointerException {
    String result = null;
    RestTemplate restTemplate = createRestTemplate();
    final String uri = apiURL + "GetInstance";

    UriComponentsBuilder builder = UriComponentsBuilder.fromHttpUrl(uri)
            .queryParam("pNo", pNo)
            .queryParam("eNo", eNo);

    HttpHeaders headers = new HttpHeaders();
    headers.add("Accept", MediaType.APPLICATION_JSON_VALUE);

    HttpEntity<String> requestEntity = new HttpEntity<>(headers);

    ResponseEntity<String> responseEntity = null;
    try {
        responseEntity = restTemplate.exchange(
                builder.toUriString(),
                HttpMethod.GET,
                requestEntity,
                String.class
        );
    } catch (RestClientException restClientException) {
        System.out.println(restClientException.getMessage());
        System.out.println(Arrays.toString(restClientException.getStackTrace()));
    }

    if (responseEntity != null) {
        if (responseEntity.getStatusCode() == HttpStatus.OK) {
            result = "true";
        } else if (responseEntity.getStatusCode() == HttpStatus.BAD_REQUEST) {
            System.out.println(responseEntity.getStatusCode().toString());
            System.out.println(responseEntity.getBody());
            result = "false";
        } else if (responseEntity.getStatusCode() == HttpStatus.NO_CONTENT) {
            System.out.println(responseEntity.getStatusCode().toString());
            System.out.println(responseEntity.getBody());
            result = "noContent";
        }
    } else if (responseEntity == null) {
        System.out.println("responseEntity is null");
        result = "false";
    }
    return result;
}

这是该方法的输出:

400 Bad Request: [{"Message":"error message"}]
[org.springframework.web.client.HttpClientErrorException.create(HttpClientErrorException.java:101),
org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:170),
org.springframework.web.client.DefaultResponseErrorHandler.handleError(DefaultResponseErrorHandler.java:112),
org.springframework.web.client.ResponseErrorHandler.handleError(ResponseErrorHandler.java:63),
org.springframework.web.client.RestTemplate.handleResponse(RestTemplate.java:782),
org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:740),
org.springframework.web.client.RestTemplate.execute(RestTemplate.java:674),
org.springframework.web.client.RestTemplate.exchange(RestTemplate.java:583),
com.xxx.xxx.App.checkPatientExistence(App.java:269), com.xxx.xxx.App.main(App.java:43)]
responseEntity is null
false

Answer 1

RestClientException没有诸如 getStatusCode() 或 getResponseBodyAsString() 之类的方法。因此，我无法在 catch block 中找到它们。

因此，我为 HttpsStatusCodeException 添加了另一个 catch block ，并颠倒了 catch block 的顺序。

HttpStatusCodeException

extends RestClientResponseException

和 RestClientResponseException

extends RestClientException

这是我们可以使用的示例方法。

} catch (HttpStatusCodeException httpStatusCodeException) {
    System.out.println(httpStatusCodeException.getStatusCode());
    System.out.println(httpStatusCodeException.getResponseBodyAsString());
    System.out.println(httpStatusCodeException.getStatusText());
    System.out.println(httpStatusCodeException.getRawStatusCode());
    System.out.println(httpStatusCodeException.getMessage());
} catch (RestClientException restClientException) {
    // catch
}