java - 如何让我的代码从食品店随机生成的数字中进行选择？

Question

当我按下按钮时，我希望它从 7 个亚洲地点之一中随机选择美食地点。当我的随机数为: 2 时，我会打印出

"Today you will eat at null".

如何让它打印出餐厅的名称并将其链接到新的 java 页面以显示其信息？

这是我声明数组的地方:

 private void createResArray() {
    Restaurant chacha = new Restaurant("Cha Cha", FoodCategory.Asian);
    Restaurant sammy = new Restaurant("Sammy Chom's K-Town", FoodCategory.Asian);
    Restaurant sushianddinsum = new Restaurant("Sushi & Dinsum", FoodCategory.Asian);
    Restaurant masterwok = new Restaurant("Master Wok", FoodCategory.Asian);
    Restaurant chinastar = new Restaurant("China Star", FoodCategory.Asian);
    Restaurant phohasaigon = new Restaurant("Pho Ha Saigon", FoodCategory.Asian);


    Restaurant taiAli = new Restaurant("Tai’s Ali's Middle East Food", FoodCategory.Middle_Eastern);
    Restaurant aliMiddle = new Restaurant("Ali's Middle East Food", FoodCategory.Middle_Eastern);
    Restaurant nycHalal = new Restaurant("NYC Halal", FoodCategory.Middle_Eastern);

    resArray = new SparseArray<Restaurant>();

    resArray.append(0, chacha);
    resArray.append(1, sammy);
    resArray.append(2, sushianddinsum);
    resArray.append(3, masterwok);
    resArray.append(4, chinastar);
    resArray.append(5, phohasaigon);


    resArray.append(6, taiAli);
    resArray.append(7, aliMiddle);
    resArray.append(8, nycHalal);
    resCount = 9;

这是我的随机数生成器:

 private void pickRestaurant(int checkedRadioButtonId) {
    Random r = new Random();
    int randomNumber = -1;

    switch (checkedRadioButtonId) {
        case R.id.Asian:
            randomNumber = r.nextInt(7)+1 ;
            break;
        case R.id.middle_eastern:
            randomNumber = r.nextInt() ;
            break;

}

    String randomRestaurantName = resArray.get(randomNumber).getName();
    Toast toast = null;
    if (randomNumber < 0) {
        toast = Toast.makeText(mContext, "Select from one of the following:",
                Toast.LENGTH_SHORT);
    } else {
        toast = Toast.makeText(mContext, "Today you will eat at "
                + randomRestaurantName , Toast.LENGTH_LONG);
    }
    toast.setGravity(Gravity.CENTER, 0, 0);
    toast.show();
}

}

Resturant.java

public class Restaurant {
private String name;
FoodCategory foodCategory;
public String getName;

public Restaurant(String name, FoodCategory priceRange) {
    this.name = name;
    this.foodCategory = priceRange;
}

public String getName()
{
    return getName;
}

protected FoodCategory getFoodCategory()
{
    return foodCategory;
}

}

Answer 1

您需要重写 Restaurant 类中的 toString() 方法，使其返回更合理的内容。