java - 如何检索列表中具有某些属性的所有对象？

Question

例如，我从服务门户创建了“事件”列表:

List<Incident> incidentObjectList = new ArrayList<>();
for (int i = 0; i < incidentNumberList.size(); i++) {
    Incident incident = new Incident();
    incident.setIncidentNumber(incidentNumberList.get(i));
    incident.setSummary(summaryList.get(i));
    incident.setRequestId(requestIdList.get(i));
    incident.setPriority(priorityList.get(i));
    incident.setLastModifiedDate(lastModifiedDateList.get(i));
    incidentObjectList.add(incident);
}
System.out.println("Incident Object List" + incidentObjectList);

每个事件都有多个属性，但我只想从由优先级低的事件对象组成的原始列表创建一个新列表。在这种情况下，incident.getPriority() 将为新列表中的所有对象返回字符串 Low。

String[] dataGreenArray = incidentObjectList.get();
retrieveTickets(dataGreenArray, listViewGreen);

Answer 1

在 Java 8 中

List<Incident> list = incidentObjectList.stream()
                                        .filter(e->e.getPriorty().equals("Low"))
                                        .collect(Collectors.toList());