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Java - 正则表达式解析字符串

转载 作者:行者123 更新时间:2023-12-01 16:47:32 26 4
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尝试用给定的样本解析名称

++++++++++++++++++SELIZABETH+COLLAZO+++++++++++++++++++
+++++++++++++++++++PALOMA+CORREA+++++++++++++++++++++++
+++++++++++++++++++NOAH+BLAKEMORE++++++++++++++++++++++

我已经尝试过

//++(.*?)+(.*?)//++

但这还很遥远。

想将名字和姓氏解析为两个字符串。

最佳答案

您可以使用此正则表达式 (\w+)\+(\w+)\+{2,}(.*?)\+(.*?)\+{ 2,} 与这样的模式:

String str = "++++++++++++++++++SELIZABETH+COLLAZO+++++++++++++++++++\n"
+ "+++++++++++++++++++PALOMA+CORREA+++++++++++++++++++++++\n"
+ "+++++++++++++++++++NOAH+BLAKEMORE++++++++++++++++++++++";

Pattern pattern = Pattern.compile("(\\w+)\\+(\\w+)");// or instead "\\+{2,}(.*?)\\+"(.*?)\\+{2,}
Matcher matcher = pattern.matcher(str);

while (matcher.find()) {
System.out.println(matcher.group(1) + " " + matcher.group(2));
}

输出

SELIZABETH COLLAZO
PALOMA CORREA
NOAH BLAKEMORE

关于Java - 正则表达式解析字符串,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47161076/

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