shell - (( COUNT++ )) -> "COUNT++: not found"在 shell 脚本中

Question

#!/bin/sh
INTERVAL=1
COUNT=0
while [ $COUNT -le 9 ]
do
    (( COUNT++ ))
    sleep $INTERVAL
    echo "count is $COUNT"
done

在执行。

$ sh ascript 
ascript: 9: COUNT++: not found
count is 0
ascript: 9: COUNT++: not found
count is 0
ascript: 9: COUNT++: not found
count is 0
ascript: 9: COUNT++: not found
count is 0
ascript: 9: COUNT++: not found
count is 0
ascript: 9: COUNT++: not found
count is 0
ascript: 9: COUNT++: not found
count is 0
ascript: 9: COUNT++: not found

Answer 1

您可能想要 #!/bin/bash而不是 #!/bin/sh如果您想使用特定于 bash 的操作，请在顶部。

您的脚本在我的 Mac 上运行良好，其中 sh真的只是bash .如果您的 sh是一个真正的你可能没有那么幸运。