java - 正则表达式查找分隔符之间包含的字符串

Question

在本文中:

text text text [[st: aaa bbb ccc ddd eee fff]] text texttext text [[st: ggg hhh iii jjj kkklll mmm nnn]] text text text

I'm trying to get the text between the [[st: and that ends with ]]

My program should output:

aaa bbb ccc ddd eee fff  (first match)ggg hhh iii jjj kkk \n lll mmm nnn(second match)

But I can only get it to return the first [[st: and the last ]], so there is just one match instead of two. Any ideas?

Here's my code:

package com.s2i.egc.test;

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class TestRegex {

    /**
     * @param args
     */
    public static void main(String[] args) {

        String bodyText = "text text text [[st: aaa bbb ccc ddd eee fff]] text text text text [[st: ggg hhh iii jjj kkk\n lll mmm nnn]] text text text";

        String currentPattern = "\\[\\[st:.*\\]\\]";

        Pattern myPattern = Pattern.compile(currentPattern, Pattern.DOTALL);

        Matcher myMatcher = myPattern.matcher(bodyText);

        int i = 1;

        while (myMatcher.find()) {
          String match = bodyText.substring(myMatcher.start() + 5, myMatcher.end() - 3);
          System.out.println(match + " (match #" + i + ")");
          i++;
        }                           


    }

}

Answer 1

量词 *(0 或更多)默认是贪婪的，因此它匹配第二个 ]]。

尝试更改为不情愿的模式匹配:

String currentPattern = "\\[\\[st:.*?\\]\\]";