java - 最小化涉及读/写操作的代码

Question

我从以下代码开始:

class Vereinfache2_edit {

    public static void main(String[] args) {

        int c1 = Integer.parseInt(args[0]);
        int c2 = Integer.parseInt(args[1]);
        int c3 = Integer.parseInt(args[2]);

        /* 1 */if (c2 - c1 == 0) {
            /* 2 */if (c1 != c3) {
                c3 += c1;
                /* 4 */System.out.println(c3);
                /* 5 */c3 *= c2;
                /* 6 */}
        }

        /* 7 */if (c1 == c3)
            /* 8 */if (c1 - c2 == 0)
            /* 9 */{
                c3 += c1;
                /* 10 */System.out.println(c3);
                /* 11 */c3 *= c1;
                /* 12 */if (c1 < c2)
                    c2 += 7;
                /* 13 */else
                    c2 += 5;
                /* 14 */}

        /* 15 */System.out.println(c1 + c2 + c3);
    }

} // end of class Vereinfache2

...我的结尾是:

class Vereinfache2 { 

        public static void main(String [] args) {

           int c1 = Integer.parseInt(args[0]) ;
           int c2 = Integer.parseInt(args[1]) ;
           int c3 = Integer.parseInt(args[2]) ;

/*  1 */       
    /*  2 */        if (c2 == c1 && c1 != c3){  
    /*  4 */              System.out.println(c3 += c2) ; 
    /*  5 */              c3 = c3 * c2 ; 
    /*  6 */        }
/*  7 */      
    /*  8 */        if ( c2 == c1 && c1 == c3){
    /* 10 */            System.out.println(c3 *= 2) ; 
    /* 11 */            c3 = c3 * c2 ; c2 = c2 + 5 ; 
    /* 14 */        }


/* 15 */       System.out.println( c1+c2+c3) ;     
        }          

}  // end of class Vereinfache2

您是否看到其他类似死代码或可切换代码的​​内容？

感谢您的所有回答。我最终得到了这个工作版本:

class Vereinfache2 { 

        public static void main(String [] args) {

           int c1 = Integer.parseInt(args[0]) ;
           int c2 = Integer.parseInt(args[1]) ;
           int c3 = Integer.parseInt(args[2]) ;

/*  1 */       if(c2 == c1){
    /*  2 */        if (c1 != c3){  
                        c3 += c2;
    /*  4 */            System.out.println(c3) ;          
    /*  6 */        }else{
                        c3 *= 2;
    /* 10 */            System.out.println(c3) ; 
    /* 14 */        }
                    c3 *= c2; c2 += 5;
               }

/* 15 */       System.out.println(c1+c2+c3) ;      
        }          

}  // end of class Vereinfache2

Answer 1

对于您的第一个版本:

      if (c2 == c1) {
        if (c1 != c3) {
          c3 += c1;
          System.out.println(c3);
          c3 *= c2;
        } else {
          c3 += c1;
          System.out.println(c3);
          c3 *= c1;
          if (c1 < c2)
            c2 += 7;
          else
            c2 += 5;
        }
      } else if (c1 < c2)
          c2 += 7;
        else
          c2 += 5;
    }
    System.out.println(c1 + c2 + c3);
  }
}

第二个版本:

           if (c2 == c1)
              if( c1 != c3){  
                System.out.println(c3 += c2) ; 
                c3 = c3 * c2 ; 
              } else {
                System.out.println(c3 *= 2) ; 
                c3 = c3 * c2 ; c2 = c2 + 5 ; 
              }
            }          

这样您就不会进行两次相同的测试。