java - 使用哪种设计模式

Question

在采访中，提出的问题是:

You have to write a program that take a directory name (e.g. D:\XYZ) and a regular expression (e.g. "Olivea") as an argument. And it will list down all the files in the given directory with the name matched with the regular expression.

我由此制作了一个简单的程序:

package temp;

import java.io.File;
import java.util.ArrayList;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class FileSearch1 {

    static ArrayList l = new ArrayList();

    public static void main(String[] args) {

        String folderName = "D:\\"; // the folder path in which you want to
                                    // search
        String strPattern = "Olivea"; // Pattern what you want to search
        final boolean searchinFile = true; // if you want to search in file keep
                                            // it true for folder search keep it
                                            // false
        File f = new File("D:\\");
        Pattern pattern1 = Pattern.compile(strPattern);
        sunny(f, pattern1, searchinFile);

    }

    public static void sunny(File f, Pattern pattern1,
            final boolean searchinFileOnly) {
        File[] f1 = f.listFiles();
        if (f1 == null)
            return;
        int k = f1.length;
        // System.out.println(k);
        int i = 0;
        while (i < k) {
            File f2 = f1[i];
            if (f2.isDirectory() && !searchinFileOnly) {
                Matcher match1 = pattern1.matcher(f2.getName());
                while (match1.find()) {
                    l.add("");
                    System.out.println(f2.getName());
                }
            } else if (f2.isFile() && searchinFileOnly) {
                Matcher match1 = pattern1.matcher(f2.getName());
                while (match1.find()) {
                    l.add("");
                    System.out.println(f2.getName());
                }
            }

            sunny(f2, pattern1, searchinFileOnly);
            i++;
        }
    }
}

笔试结束后，面试官问我哪个设计您可以在此使用模式。请您向我推荐各种我们可以在这段代码中实现哪些设计模式？

请帮助我如何在此应用复合和迭代器模式？非常感谢您的帮助

Answer 1

忽略您错过了编码的第一条黄金法则(即所有内容都应该正确命名)的事实，您可以使用 Iterator和Composite模式。

复合将允许以类似的方式处理文件和目录。

迭代器用于遍历容器并访问容器的元素。迭代器模式将算法与容器解耦。