java - 重新绘制 JPanel

Question

我想重新绘制我的 jPanel我有一个处理此 JFrame 中显示的屏幕的 App 类，我添加了一个处理所有 JPanel 的 Board JPanel 对象。在董事会类(class)中我有

ex = new Explosion(10, 10); 
new Thread(ex).start();

在我的 Explosion 类中，我有一个构造函数来裁剪我的 Sprite 文件，覆盖 Paint() 和:

public void run()
    {
        while(cursor < (rows*cols))
        {
            repaint();

            try {
                Thread.sleep(100);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }

            System.out.println(cursor);

            cursor++;
        }
    }

循环工作正常，但我的屏幕上没有重新绘制，只显示第一个图像。

我可以做什么来刷新？

谢谢

编辑:这是我的代码:

public class Explosion extends JPanel implements Runnable{

private BufferedImage img;

final int width = 320;
final int height = 320;
final int rows = 5;
final int cols = 5;

private int x,y;

private int cursor;

BufferedImage[] sprites = new BufferedImage[rows * cols];

public Explosion(int x, int y)
{
    this.x = x;
    this.y = y;

    try {
        try {
            this.img = ImageIO.read(new File((this.getClass().getResource("files/explosion2.png")).toURI()));
        } catch (URISyntaxException e) {
            e.printStackTrace();
        }
    } catch (IOException e) {
        e.printStackTrace();
    }

    cursor = 0;

    for (int i = 0; i < rows; i++)
    {
        for (int j = 0; j < cols; j++)
        {
            sprites[(i * cols) + j] = img.getSubimage(
                i * (width/rows),
                j * (height/cols),
                width/rows,
                height/cols
            );
        }
    }
}

public void run()
{
    ActionListener taskPerformer = new ActionListener() {
          public void actionPerformed(ActionEvent evt) {
              cursor++;
              repaint();
          }
      };

    while(cursor < (rows*cols))
    {           
          new Timer(50, taskPerformer).start();


        if (cursor==(rows*cols)-1)
            cursor=0;
    }
}

public void paintComponent(Graphics g){
    System.out.println("paintComponent");
    Graphics2D g2d = (Graphics2D)g;
    g2d.drawImage(sprites[cursor], x, y, this);
    g.dispose();    
}

/*public void paint(Graphics g) {
        super.paint(g);

        System.out.println("paint");

        Graphics2D g2d = (Graphics2D)g;
        g2d.drawImage(sprites[cursor], x, y, this);
        Toolkit.getDefaultToolkit().sync();
        g.dispose();        
}*/


}
public class Main extends JFrame{

    public Main() 
    {
        Board board = new Board();
        add(board);
        setTitle("Explosion");
        setSize(500, 500);
        setLocationRelativeTo(null);
        setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        setVisible(true);  
    }

    public static void main(String[] args) {
        new Main();
    }

}
public class Board extends JPanel{

    Explosion ex;

    public Board() 
    {           
        setDoubleBuffered(true); 

        ex = new Explosion(10,10);
        new Thread(ex).start();
    }

    public void paint(Graphics g) {
        ex.paintComponent(g);

        super.paint(g);
        Graphics2D g2d = (Graphics2D)g;
        Toolkit.getDefaultToolkit().sync();
        g.dispose();
    }
}

Answer 1

@StanislavL(我还不能发表评论):不，你不必在 EDT 中调用 repaint():

The following JComponent methods are safe to call from any thread: repaint(), revalidate(), and invalidate(). The repaint() and revalidate() methods queue requests for the event-dispatching thread to call paint() and validate(), respectively. The invalidate() method just marks a component and all of its direct ancestors as requiring validation.

来源:http://java.sun.com/products/jfc/tsc/articles/threads/threads1.html#exceptions

cursor 是否声明为 volatile ？如果不是，EDT 可能看不到线程对光标所做的更改。因此，始终绘制第一个图像。