java - Spring WebClient : Passing username and password in request body to get a token

Question

遵循 Spring WebClient 教程 here我正在尝试将请求正文中的用户名和密码(无基本身份验证)传递到 API 端点，因为它需要这些作为参数。

我已经在 Postman 中进行了测试，将用户名和密码作为正文中的单独字段提供，并将 contentType 设置为 application/x-www-form-urlencoded。这会导致获得预期的 token ，但是当我使用 WebClient 的实现打印出下面的响应时，它会打印:

{"error":"invalid_request","error_description":"Missing form parameter: grant_type"}

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TcpClient tcpClient = TcpClient.create().option(ChannelOption.CONNECT_TIMEOUT_MILLIS, CONNECTION_TIMEOUT_MILIS)
                .doOnConnected(connection -> {
                    connection.addHandlerLast(new ReadTimeoutHandler(CONNECTION_TIMEOUT_MILIS, TimeUnit.MILLISECONDS));
                    connection.addHandlerLast(new WriteTimeoutHandler(CONNECTION_TIMEOUT_MILIS, TimeUnit.MILLISECONDS));
                });

        WebClient client = WebClient.builder().baseUrl(BASE_URL)
                .defaultHeader(HttpHeaders.CONTENT_TYPE, MediaType.APPLICATION_FORM_URLENCODED_VALUE)
                .clientConnector(new ReactorClientHttpConnector(HttpClient.from(tcpClient))).build();           


        LinkedMultiValueMap<String, String> multiMap = new LinkedMultiValueMap<>();

        multiMap.add("username", username);
        multiMap.add("password", password);

        BodyInserter<MultiValueMap<String, Object>, ClientHttpRequest> inserter = BodyInserters.fromMultipartData(multiMap);


        WebClient.RequestHeadersSpec<?> request = client.post().uri(API_CALL_GET_TOKEN).body(inserter);


        String response = request.exchange().block().bodyToMono(String.class).block();
        System.out.println(response);

Answer 1

提供.accept(MediaType.APPLICATION_JSON)提供了响应:

WebClient client = WebClient.create();

LinkedMultiValueMap<String, String> credentials = new LinkedMultiValueMap<>();

credentials.add("username", username);
credentials.add("password", password);

String response = client.post()
      .uri(BASE_URL + API_CALL_GET_TOKEN)
      .contentType(MediaType.APPLICATION_FORM_URLENCODED)
      .accept(MediaType.APPLICATION_JSON)
      .body(BodyInserters.fromFormData(credentials))
      .retrieve()
      .bodyToMono(String.class)
      .block();

return response;