java - 字符串数组以及如何循环它们

Question

我想知道是否可以为我想在代码中计算的字符串数组创建一个循环。我想一次处理多个二进制数。到目前为止，我的工作正常，但是我不知道如何让它一次评估多个二进制数。谢谢。

 package twoComplement;

public class bintodec {

public static void main (String[] args)throws java.io.IOException {

int number,
    digit1,
    digit2,
    digit3,
    digit4,
    digit5,
    digit6,
    digit7,
    digit8,
    result;

String num = "11100111";

number = Integer.parseInt(num);

digit1 = ((number % 100000000) - (number % 10000000 % 10000000)) / 10000000;
digit2 = ((number % 10000000) - (number % 10000000 % 1000000)) / 1000000;
digit3 = ((number % 1000000) - (number % 1000000 % 100000)) / 100000;
digit4 = ((number % 100000) - (number % 100000 % 10000)) / 10000;
digit5 = ((number % 10000) - (number % 10000 % 1000)) / 1000;
digit6 = ((number % 1000) - (number % 1000 % 100)) / 100;
digit7 = ((number % 100) - (number % 100 % 10)) / 10;
digit8 = (number % 10);

result = (digit1 * -128) + (digit2 * 64) + (digit3 * 32) + (digit4 * 16) + (digit5 * 8) + (digit6 * 4) + (digit7 * 2) + (digit8 * 1);

System.out.println ( "Binary number: " + num + "\nDecimal Number: " + result);
System.out.println();
System.exit( 0 );

}
}

Answer 1

是的，这就是循环的目的；-) 高级 for 循环是迭代数组的最佳方法。您还可以迭代集合(IE:ArrayList)，这使得添加新项目变得更加容易。

String[] numbersToEvaluate = new String[]{"11100111", "100101", "10101101"};

for (String num: numbersToEvaluate)
{
    number = Integer.parseInt(num);

    digit1 = ((number % 100000000) - (number % 10000000 % 10000000)) / 10000000;
    digit2 = ((number % 10000000) - (number % 10000000 % 1000000)) / 1000000;
    digit3 = ((number % 1000000) - (number % 1000000 % 100000)) / 100000;
    digit4 = ((number % 100000) - (number % 100000 % 10000)) / 10000;
    digit5 = ((number % 10000) - (number % 10000 % 1000)) / 1000;
    digit6 = ((number % 1000) - (number % 1000 % 100)) / 100;
    digit7 = ((number % 100) - (number % 100 % 10)) / 10;
    digit8 = (number % 10);

    result = (digit1 * -128) + (digit2 * 64) + (digit3 * 32) + (digit4 * 16) + (digit5 * 8) + (digit6 * 4) + (digit7 * 2) + (digit8 * 1);

    System.out.println ( "Binary number: " + num + "\nDecimal Number: " + result);
}