java - 如何在 hibernate 搜索中实现对 int 值的搜索？

Question

我正在尝试搜索整数值。我已经用 @Field 注释了参数，如下所示:

@Field(name = "confirmedCount", index = UN_TOKENIZED, store = Store.YES)
public int getConfirmedCount() {
   return stuff.size();
}

然后我使用 luke 执行范围搜索:

confirmedCount:[5 TO 100]

我返回的结果是空的。然后我尝试:

confirmedCount:[1 TO 2]

结果是:

name confirmedCount
b    1
a    1
d    19
c    2

所以我的问题是:为什么我会收到此回复以及如何解决？我使用hibernate搜索3.0.1.GA

Answer 1

好吧，我想我的问题的答案是 RTFM!文档明确指出:

Numbers are converted into their string representation. Note that numbers cannot be compared by Lucene (ie used in ranged queries) out of the box: they have to be padded

所以我们需要实现一个类桥:

public class PaddedIntegerBridge implements StringBridge {

    private int PADDING = 5;

    public String objectToString(Object object) {
        String rawInteger = ( (Integer) object ).toString();
        if (rawInteger.length() > PADDING)
            throw new IllegalArgumentException( "Try to pad on a number too big" );
        StringBuilder paddedInteger = new StringBuilder( );
        for ( int padIndex = rawInteger.length() ; padIndex < PADDING ; padIndex++ ) {
            paddedInteger.append('0');
        }
        return paddedInteger.append( rawInteger ).toString();
    }
}

然后我们需要注释该字段，以便它被索引:

@Field(name = "confirmedCount", index = UN_TOKENIZED, store = Store.YES, bridge = @FieldBridge(impl = PaddedIntegerBridge.class))
    public int getConfirmedCount() {
        return stuff.size();
    }

然后在我的搜索中，我只需要在创建查询时使用这个桥，瞧它有效 =)

与 Luke 的一些测试:

confirmedCount:[00005 TO 00100]

name confirmedCount
g    00006
d    00019