java - 在java中读取txt文件，程序跳过第一行

Question

这个问题已经有答案了:

Scanner is skipping nextLine() after using next() or nextFoo()? (25 个回答)

已关闭 3 年前。

我的程序正在跳过 .txt 文件的第一行。这是我的代码应该从 .txt 文件读取的位置。

static int getPints(int[] pints) throws IOException {
    Scanner inputFile = new Scanner(new File("BloodInFile.txt"));
    int count = 0;
    while (inputFile.hasNext()) {
        pints[count] = inputFile.nextInt();
        count++;
    }
    return pints[count];
}

它应该读取 7 个整数，但我只读取了其中 6 个。其余代码有效，但我不确定如何让它读取第一个整数。

这是我的其余代码:

static int getPints(int[] pints) throws IOException {
    Scanner inputFile = new Scanner(new File("BloodInFile.txt"));
    int count = 0;
    while (inputFile.hasNext()) {
        pints[count] = inputFile.nextInt();
        count++;
    }
    inputFile.close();
    return pints[count];
}

static double getAverage(int pints[], int MAX_HOURS) {
    int counter;
    double totalPints = 1;
    double averagePints;
    for (counter = 1; counter < MAX_HOURS - 1; counter++) {
        System.out.println("pints:" + pints[counter]);
        totalPints = totalPints + pints[counter];
    }
    averagePints = totalPints / (MAX_HOURS - 2);
    System.out.println("Total pints: " + totalPints);
    return averagePints;
}

static double getHigh(int pints[], int MAX_HOURS) {
    int index = 1;
    double highest = pints[index];
    for (index = 1; index < MAX_HOURS - 1; index++) {
        if (pints[index] > highest) {
            highest = pints[index];
        }
    }
    return highest;
}

static double getLow(int pints[], int MAX_HOURS) {
    int index = 1;
    double lowest = pints[index];
    for (index = 1; index < MAX_HOURS - 1; index++) {
        if (pints[index] < lowest) {
            lowest = pints[index];
        }
    }
    return lowest;
}

Answer 1

我就这样做过一次，也许这也适合你

public static List<String> get16TeamsFromTxt() throws IOException {
    Path currentRelativePath = Paths.get("");
    String s1 = currentRelativePath.toAbsolutePath().normalize().toString();

    Scanner s = new Scanner(new File(s1+"/16.txt"));
    ArrayList<String> list = new ArrayList<String>();
    while (s.hasNextLine()){
        list.add(s.nextLine());
    }
    s.close();

    return list;

}

这样您就可以获得包含所有号码的列表。我的是字符串，但应该与整数一起使用。