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java - JPA Criteria 查询分组依据并获取最后一条记录

转载 作者:行者123 更新时间:2023-12-01 16:28:23 25 4
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该实体员工

@Entity
@Table(name="employee")
@IdClass(EmployeeKey.class)
public class Employee implements Serializable{
private static final long serialVersionUID = -4060941180859761486L;

@Id @Column(name ="DATA_DT")
private Date registDate;
@Id @Column(name ="EMPE_NO")
private String empeId;

@Column(name ="TTL_NM_TH")
private String titleNameTh;
@Column(name ="TTL_NM_EN")
private String titleNameEn;
@Column(name ="EMPE_NM_TH")
private String empeNameTh;
@Column(name ="EMPE_LST_NM_TH")
private String empeLastNameTh;
@Column(name ="EMPE_POS")
private String empePosition;


@ManyToOne
@JoinColumn(name = "DEPT_CODE" , nullable = true)
@NotFound(action = NotFoundAction.IGNORE)
private OrganizationUnit empeDeptCode;


//get set

}

this entity ou

@Entity
@Table(name="ou")
public class OrganizationUnit implements Serializable{
private static final long serialVersionUID = -4038118923332034407L;
@Id
@Column(name ="OU_CODE")
private String ouCode;
@Column(name ="OU_TP_CODE")
private String ouTpCode;
@Column(name ="OU_NM")
private String ouName;
@Column(name ="BR_GRP")
private String ouBusinessGroup;
@Column(name ="GRP_OU_CODE")
private String groupOUCode;
@Column(name ="SCTR_OU_CODE")
private String sctrOUCode;
@Column(name ="DEPT_OU_CODE")
private String departmentOUCode;
@Column(name ="EFF_DT")
private Date effectiveDate;
@Column(name ="END_DT")
private Date endDate;

//get set

}

现在我创建一个像这样的条件查询。我尝试从 criteria-Api 创建搜索功能。我的表employee有两个id,每天我都会在employee中插入数据。搜索功能需要显示最后一条记录。

public List<Employee> findByAvanceSearch(SearchEmpRequestModel data) {
// TODO Auto-generated method stub
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<Employee> cq = cb.createQuery(Employee.class);


Root<Employee> employee = cq.from(Employee.class);
List<javax.persistence.criteria.Predicate> predicates = new ArrayList<>();

if(data.getEmpNumber() != null) {

//predicates.add( cb.and(cb.equal(employee.get("empeId"), data.getEmpNumber()), cb.greatest(employee.get("registDate"))));
predicates.add(cb.equal(employee.get("empeId"), data.getEmpNumber()));
}
if(data.getEmpThainame()!=null) {

predicates.add(cb.like(employee.get("titleNameTh"), "%"+data.getEmpThainame()+"%"));
}
if(data.getEmpDept()!=null) {

predicates.add(cb.like(employee.get("empeDeptCode").get("departmentOUCode"), "%"+data.getEmpDept()+"%"));

}
if(data.getEmpGrp()!=null) {

predicates.add(cb.like(employee.get("empeDeptCode").get("sctrOUCode"), "%"+data.getEmpGrp()+"%"));

}
if(data.getEmpSctr()!=null) {

predicates.add(cb.like(employee.get("empeDeptCode").get("groupOUCode"), "%"+data.getEmpSctr()+"%"));

}


cq.orderBy(cb.asc(employee.get("registDate"))).groupBy(employee.get("empeId")).where((javax.persistence.criteria.Predicate[]) predicates.toArray(new javax.persistence.criteria.Predicate[0]));
return em.createQuery(cq).getResultList();
}

我需要从分组中获取最后一条记录,但从这段代码中我得到了第一条记录。任何人都知道我应该在 hibernate 标准中使用什么?谢谢。

最佳答案

使用子查询通过使用 max 和 groupby 来查找 id,希望对某人有帮助

subquery.select(cb.max(subroot.get("id")))
.where(predicates.stream().toArray(Predicate[]::new))
.groupBy(subRoot.get("empid"));

关于java - JPA Criteria 查询分组依据并获取最后一条记录,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62114800/

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