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C# 随机数生成器

转载 作者:行者123 更新时间:2023-12-01 16:26:52 26 4
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我使用以下代码生成 4 个随机数,但每次我尝试获取它们时,它们都会在文本 block 中显示为“system.random”。帮助任何人吗?谢谢!! :)

private void Button_Click_1(object sender, RoutedEventArgs e)        
{
Random dc1 = new Random();
int dealCard1 = dc1.Next(52);

Random dc2 = new Random();
int dealCard2 = dc2.Next(52);

Random pc1 = new Random();
int playerCard1 = pc1.Next(52);

Random pc2 = new Random();
int playerCard2 = pc2.Next(52);

txtDC1.Text = Convert.ToString(dc1);
txtDC2.Text = Convert.ToString(dc2);
txtPC1.Text = Convert.ToString(pc1);
txtPC2.Text = Convert.ToString(pc2);
}

最佳答案

首先,您只需要一个随机实例:

Random dc1 = new Random();
int dealCard1 = dc1.Next(52);
int dealCard2 = dc1.Next(52);
int playerCard1 = dc1.Next(52);
int playerCard2 = dc1.Next(52);

错误是因为您没有报告数字:

txtDC1.Text = Convert.ToString(dealCard1);
txtDC2.Text = Convert.ToString(dealCard2);
txtPC1.Text = Convert.ToString(playerCard1);
txtPC2.Text = Convert.ToString(playerCard2);

关于C# 随机数生成器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23530244/

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