java - 智能读取 XML 并将其转换为 JSON

Question

我有代码可以进行格式化并将 XML 转换为 JSON，但它很大且昏昏欲睡。我需要从 XML 中挑选大约 50 个元素，并使用这些元素格式化 JSON。很多部分是重复的，但元素不同。下面是代码:-

private String createBrokeredMessage(String payload) {
    String message = "";
    String Ver = "";
    String ID = "";
            |
            |   
    String Rec = "";
    String default1 = "[]";

    try {
        DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
        InputSource src = new InputSource();
        src.setCharacterStream(new StringReader(payload));

        Document doc = builder.parse(src);
        NodeList n1 = doc.getElementsByTagName("Ver");
        if (n1.getLength() > 0) {
            Ver = n1.item(0).getTextContent();
            if(Ver == "") {
                Ver = default1;
            }
            else {
                Ver = "\""+Ver+"\"";
            }
        }

        NodeList n2 = doc.getElementsByTagName("ID");
        if (n2.getLength() > 0) {
            ID = n2.item(0).getTextContent();
            if(ID == "") {
                ID = default1;
            }
            else {
                ID = "\""+ID+"\"";
            }
        }
        //|
        //|
        //|
        //|
        //|
        //|

        NodeList n49 = doc.getElementsByTagName("Rec");
        if (n49.getLength() > 0) {
            Rec = n49.item(0).getTextContent();
            if(Rec == "") {
                Rec = default1;
            }
            else {
                Rec = "\""+Rec+"\"";
            }
        }

        message = "{\"Envelope\":{\"Ver\":"+Ver+",\"ID\":"+ID+-------------------",\"Rec\":"+Rec+"}]}";
        System.out.println("Created message with ID" + message);
    } catch (Exception e){
            e.printStackTrace();
    }

    return message;
}

示例 XML:-

<?xml Version="1.0" encoding="UTF-8" standalone="no"?>
<Data xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <Envelope>
    <Ver>1.13</Ver>
    <ID>SAO</ID>
    <Rec>men</Rec>
    <TransactionID>0987714805168</TransactionID>
  </Envelope>
  <Code>124</Code>
  <City></City>
  <CompCodes>
    <CompCode>US</CompCode>
    <Vend>13</Vend>
  </CompCodes>
  <BankData>
    <Code>123</Code>
    <BankAcctNum>231</BankAcctNum>
  </BankData>
  <BankData>
    <Code>124</Code>
    <BankAcctNum>431</BankAcctNum>
  </BankData>
</Data>

输出 JSON:-

{
   "Envelope": {
      "Ver": "1.13",
      "ID": "SAO",
      "Rec": "men",
      "TransactionID": "0987714805168"
   },
   "Code": "124",
   "City": [],
   "CompCodes": [{
      "CompCode": "US",
      "Vend": "13"
   }],
   "BankData": [
      {
         "Code": "123",
         "BankAcctNum": "231"
      },
      {
         "Code": "124",
         "BankAcctNum": "431"
      }
   ]
}

任何帮助将不胜感激!

Answer 1

您可以使用 JSON Jackson 将 XML 快速轻松地转换为 JSON。

public static void main(String[] args) {
    String xml = "<?xml Version=\"1.0\" encoding=\"UTF-8\" standalone=\"no\"?>\n"
        + "<Data xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\">\n"
        + "  <Envelope>\n"
        + "    <Ver>1.13</Ver>\n"
        + "    <ID>SAO</ID>\n"
        + "    <Rec>men</Rec>\n"
        + "    <TransactionID>0987714805168</TransactionID>\n"
        + "  </Envelope>\n"
        + "  <Code>124</Code>\n"
        + "  <City></City>\n"
        + "  <CompCodes>\n"
        + "    <CompCode>US</CompCode>\n"
        + "    <Vend>13</Vend>\n"
        + "  </CompCodes>\n"
        + "  <BankData>\n"
        + "    <Code>123</Code>\n"
        + "    <BankAcctNum>231</BankAcctNum>\n"
        + "  </BankData>\n"
        + "  <BankData>\n"
        + "    <Code>124</Code>\n"
        + "    <BankAcctNum>431</BankAcctNum>\n"
        + "  </BankData>\n"
        + "</Data>";

    JSONObject json = XML.toJSONObject(xml);
    System.out.println(json.toString());
}

添加依赖:

<dependency>
    <groupId>org.json</groupId>
    <artifactId>json</artifactId>
    <version>20200518</version>
</dependency>

请参见此处:https://www.techiedelight.com/convert-xml-to-json-in-java/