ios - 快速使用NSMutableArray

Question

我有一个字符串的NSMutableArray skippedArray。

skipped Array = ["string1","string2","string3","string4"];

我想将索引0处的字符串分配给 UILabel。

我尝试了 lblQuestion.text = skippedArray[j] as! String但该应用程序在此行崩溃。

有人可以帮忙吗？

Answer 1

像这样定义NSMutableArray:

let skippedArray = ["string1","string2","string3","string4"];
lblQuestion.text =  skippedArray.first

或者您也可以这样编写代码:

let skippedArray : NSMutableArray =         ["string1","string2","string3","string4"];
lblQuestion.text =  skippedArray.firstObject as! String

还有另一种获取NSMutableArray对象的方法，如下所示:

let skippedArray : NSMutableArray = ["string1","string2","string3","string4"];
 let j = 0;
lblQuestion.text =  skippedArray.object(at: j) as! String