java - 如何打开和关闭fragment，点击android中的同一个按钮

Question

如何在单击同一按钮时打开和关闭 fragment 。就像亚马逊的过滤按钮一样。当我们第一次单击时， fragment 应该出现，然后我们再次单击该按钮， fragment 应该消失。

业务 Activity java文件

public class business extends AppCompatActivity {

TextView t1, t2;
Button hello;
boolean flag = false;
FragmentTransaction fragmentTransaction;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_business);
    hello = findViewById(R.id.hello);
    t1=findViewById(R.id.text1);
    t2=findViewById(R.id.textt2);

}

@Override
protected void onStart() {
    super.onStart();
    hello.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            FragmentManager manager = getSupportFragmentManager();
            BusinessSort businessSort = new BusinessSort();
            fragmentTransaction = manager.beginTransaction();
            if (flag) {
                fragmentTransaction.remove(businessSort);
                flag=false;
            } else {
                fragmentTransaction.add(R.id.frgmCont, businessSort);
                flag=true;
            }
            fragmentTransaction.commit();
        }
    });

}


public void f1(String s1, String s2) {
    t1.setText(s1);
    t2.setText(s2);
}

}

activity_business.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".business"
android:orientation="vertical"
android:id="@+id/businessLinearLayout">
<Button
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:text="hello"
        android:id="@+id/hello"
/>

<TextView
    android:id="@+id/text1"
    android:layout_width="match_parent"
    android:layout_height="50dp"
    android:text="edit1"/>
<TextView
    android:layout_width="match_parent"
    android:layout_height="50dp"
    android:text="edit2"
    android:id="@+id/textt2"/>

<FrameLayout
    android:id="@+id/frgmCont"
    android:layout_width="match_parent"
    android:layout_height="match_parent">
</FrameLayout>

fragment 文件BusinessSort.java

public class BusinessSort extends Fragment {

EditText editText1,editText2;
Button submit;
 @Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
                         Bundle savedInstanceState) {
    // Inflate the layout for this fragment
    View view =inflater.inflate(R.layout.fragment_business_sort, container, false);
    editText1=view.findViewById(R.id.edit1);
    editText2=view.findViewById(R.id.edit2);
    submit=view.findViewById(R.id.businessfragment_submit);
    submit.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            String s1 = editText1.getText().toString();
            String s2 = editText2.getText().toString();
            business business = (com.example.project.business) getActivity();
            business.f1(s1,s2);

        }
    });

    return view;
}

fragment_business_sort.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".BusinessSort"
android:orientation="vertical">

<EditText
    android:id="@+id/edit1"
    android:layout_width="match_parent"
    android:layout_height="50dp"/>
<EditText
    android:id="@+id/edit2"
    android:layout_width="match_parent"
    android:layout_height="50dp"/>
<Button
    android:id="@+id/businessfragment_submit"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:text="SUBMIT"/>
</LinearLayout>

Answer 1

尝试替换 fragment 。

 fragmentTransaction.replace(R.id.frgmCont, businessSort);
 flag = true;

我希望代码与我的方法基本相似，因此请告诉我问题是否仍然存在，以便我更深入地研究它。